3 years ago

Which of the following can be a component of soil?

Physics

1 answer:

Evgen [1.6K]3 years ago

3 0

Answer: what are the answers?

Explanation:

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Two resistors, R1 = 25.0 ohms and

Leni [432]

Answer: 0.078

Explanation:

Given variables:

R1 = 25.0 , R2 = 64.0 , I1 = 0.200

Step 1: find V

0.200 = v/25

0.200 * 25 = v

5 = v

Step 2: Solve for I2

I = V/R

I = 5/64

I = 0.078125

Hope this helps!

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3 years ago

In this equation, what shows that transmutation has taken place?

kaheart [24]

Answer:

The completed equations are as follows: 2713Al+42He⟶3015P+10n 13 27 Al + 2 4 He ⟶ 15 30 P + 0 1 n; 23994Pu+42He⟶24296Cm+10n 94 239 Pu + 2 4 He ⟶ 96 242 Cm + 0 1 n; 147N+42He⟶178O+11H 7 14 N

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3 years ago

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Two rings of radius 5 cm are 20 cm apart and concentric with a common horizontal x-axis. The ring on the left carries a uniforml

Yanka [14]

Answer:

The electric field due to the right ring at a location midway between the two rings is $2.41\times10^{3}\ V/m$

Explanation:

Given that,

Radius of first ring = 5 cm

Radius of second ring = 20 cm

Charge on the left of the ring = +30 nC

Charge on the right of the ring = -30 nC

We need to calculate the electric field due to the right ring at a location midway between the two rings

Using formula of electric field

$E=\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{qx}{(x^2+R^2)^{\frac{3}{2}}}$

Put the value into the formula

$E=\dfrac{9\times10^{9}\times30\times10^{-9}\times0.1}{((0.1)^2+(0.2)^2)^{\frac{3}{2}}}$

$E=2.41\times10^{3}\ V/m$

Hence, The electric field due to the right ring at a location midway between the two rings is $2.41\times10^{3}\ V/m$

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4 years ago

Which biome's yearly rainfall mainly evaporates?

tino4ka555 [31]

India's monsoon area i beleive

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4 years ago

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What's the name of a star that does 'not move'?

Arte-miy333 [17]

Answer:

i also don't known ....

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3 years ago