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3 years ago

Two resistors, R1 = 25.0 ohms and

Physics

1 answer:

Leni [432]3 years ago

3 0

Answer: 0.078

Explanation:

Given variables:

R1 = 25.0 , R2 = 64.0 , I1 = 0.200

Step 1: find V

0.200 = v/25

0.200 * 25 = v

5 = v

Step 2: Solve for I2

I = V/R

I = 5/64

I = 0.078125

Hope this helps!

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Water flows over a section of niagara falls at the rate of 1.2x10^6 and falls 50.0 m. how much power is generated by the falling

iren [92.7K]

The solution for this is:

Power = Energy transferred / Time taken

Energy Transferred in one second ( Power) = mgh/s

= (1.2x10^6)(9.8)(50) = 588000000 J/s

Power = 588000000 W

Power is work done / time

Work done in one second = [ rate of fall of mass]

gh = 1.2* *9.81*50 x 10^6 J/s

= 5.886e+8 W

6 0

3 years ago

A balloon filled with helium gas has an average density of rhob = 0.22 kg/m3. The density of the air is about rhoa = 1.23 kg/m3.

MissTica

Answer:

$a=g\left(\frac{\rho_a}{\rho_b}-1\right)$

45.03681 m/s²

Explanation:

$F_b$ = Buoyant force

W = Weight of the balloon

$\rho_a$ = Density of air = 1.23 kg/m³

$\rho_b$ = Density of balloon = 0.22 kg/m³

$v_a$ = Volume of air

$v_b$ = Volume of balloon

$F_b=\rho_av_bg$

$W=\rho_bv_bg$

g = Acceleration due to gravity = 9.81 m/s²

The net force acting on the balloon is

$F=F_b-W\\\Rightarrow F=\rho_av_bg-\rho_bv_bg\\\Rightarrow \rho_bv_ba=\rho_av_bg-\rho_bv_bg\\\Rightarrow \rho_bv_ba=v_bg(\rho_a-\rho_b)\\\Rightarrow a=\frac{g}{\rho_b}(\rho_a-\rho_b)\\\Rightarrow a=g\left(\frac{\rho_a}{\rho_b}-1\right)$