Question

In the Bohr model of the hydrogen atom, the speed of the electron is approximately 2.2 106 m/s.

Answer 1

The central force acting on the electron as it revolves in a circular orbit is $9.52 \times 10^{-8} \ N$.

The given parameters;

• speed of electron, v = 2.2 x 10⁶ m/s
• radius of the circle, r = 4.63 x 10⁻¹¹ m

The central force acting on the electron as it revolves in a circular orbit is calculated as follows;

$F = \frac{M_e v^2}{r}$

where;

$M_e$ is mass of electron = 9.11 x 10⁻³¹ kg

$F = \frac{(9.11 \times 10^{-31}) \times(2.2\times 10^6)^2 }{4.63 \times 10^{-11}} \\\\F = 9.52 \times 10^{-8} \ N$

Thus, the central force acting on the electron as it revolves in a circular orbit is $9.52 \times 10^{-8} \ N$.

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