A truck pushes a pile of dirt horizontally on a frictionless road with a net force of
1 answer:
Answer:
<h2>300 Joules</h2>Explanation:
This is a common question on Khan Academy's "Calculating change in kinetic energy from a force" practice exercises. (AP Physics 1)
- The simplest method to use is the following:
, where W represents work (joules), F represents force (newtons), d represents distance (meters), and theta represents the angle of the force that's being applied.
- In this scenario, the force being applied is horizontal, so we can remove the
from our equation.
- So, our equation is now:
. This would mean that
, which is equal to
.
- Our answer is 300 joules. (this value is positive and not negative because kinetic energy is being GAINED, not LOST)
Here's the real question without all the formatting:
- A truck pushes a pile of dirt horizontally on a frictionless road with a net force of 20 N for 15.0 m. How much kinetic energy does the dirt gain?
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Answer:
18.33 Ns
Explanation:
As the pitch back speed has the opposite direction as before, the change in velocity would be
So the change in momentum of the ball would be the product of its velocity change and its mass
This is equals to the impulse acted on the ball by the bat, which is 18.33 Ns
Let the first car's average speed be x
The second car's speed would be x+5
So the speed of the slower car is 50mph, and the speed of the faster car is 55mph
The second car's speed would be x+5
So the speed of the slower car is 50mph, and the speed of the faster car is 55mph