Ahh I’m not smart so imma just guess not saying it’s right . 24 in?
D) f(n) = 3 + 4(n-1)
3 = 1st term
4 = common difference among the terms
n = term number you are looking for.
To check: 3, 7, 11, 15, ...
f(1) = 3 + 4(1-1) = 3 + 4(0) = 3 + 0 = 3
f(2) = 3 + 4(2-1) = 3 + 4(1) = 3 + 4 = 7
f(3) = 3 + 4(3-1) = 3 + 4(2) = 3 + 8 = 11
f(4) = 3 + 4(4-1) = 3 + 4(3) = 3 + 12 = 15
Answer:
x = 1
y = 4
Step-by-step explanation:
5x + 2y = 13
x + 2y = 9
Add both equations.
6x + 4y = 22
Solve for x.
6x = 22 - 4y
x = 22/6 - 4/6y
Put x as 22/6 - 4/6y in the second equation and solve for y.
22/6 - 4/6y + 2y = 9
-4/6y + 2y = 9 - 22/6
4/3y = 16/3
y = 16/3 × 3/4
y = 48/12
y = 4
Put y as 4 in the first equation and solve for x.
5x + 2(4) = 13
5x + 8 = 13
5x = 13 - 8
5x = 5
x = 5/5
x = 1
His error is he forgot the 2 in 2 3/4
If n>4
Then n/4>7
I guess dis is the answer
