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pishuonlain [190]
3 years ago
8

There are a few ways to increase the rate of a reaction. When the amount of a substance in a given volume is increased, this is

altering the__________.
Mathematics
2 answers:
fiasKO [112]3 years ago
6 0

Answer:

Concentration.

Step-by-step explanation:

Concentration: It is define as the amount of substance  per unit volume.

Or

Concentration is defined as the ratio of solute in a solution to either solvent or total solution.

Concentration usually is expressed in terms of mass per unit volume.

When the amount of a substance in a given volume is increased then it alter the concentration of reactant.When the concentration of reactant is increase then the rate of reaction  increases.Because when the concentration is increases then more ions or molecules interact to form new compounds therefore, the rate of reaction  increases.When the concentration of reactant decrease then less number of ions or molecules interact to form new compounds therefore, the rate of reaction decreases.

RUDIKE [14]3 years ago
4 0
Both of these variables represent a common measure used in chemistry.

The amount of material/volume is the material’s concentration.

The rate is the reaction is increase by altering the concentration.
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Answer:

Probability that the mean daily precipitation will be 0.09 inches or less for a random sample of 40 November days is 0.103.

Step-by-step explanation:

We are given that according to records, the amount of precipitation in a certain city on a November day has a mean of 0.10 inches; with a standard deviation of 0.05 inches.

A random sample of 40 November days is taken(taken over many years).

<u><em>Let </em></u>\bar X<u><em> = sample mean daily precipitation</em></u>

The z score probability distribution for sample mean is given by;

                                 Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean = 0.10 inches

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Now, the probability that the mean daily precipitation will be 0.09 inches or less is given by = P( \bar X \leq 0.09 inches)

 P(\bar X \leq 0.09 inches) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \leq \frac{0.09-0.10}{\frac{0.05}{\sqrt{40} } } ) = P(Z \leq -1.265) = 1 - P(Z < 1.265)

                                                                    = 1 - 0.8971 = <u>0.1029</u>

<em>The above probability is calculated by looking at the value of x = 1.265 from the z table which will lie between x = 1.26 and x = 1.27 which has an area of 0.89617 and 0.89796 respectively.</em>

Hence, the probability that the mean daily precipitation will be 0.09 inches or less for a random sample of 40 November days is 0.103.

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