![\stackrel{\textit{\LARGE Line A}}{(\stackrel{x_1}{-8}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{-5}~,~\stackrel{y_2}{4})} ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{4}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{-5}-\underset{x_1}{(-8)}}} \implies \cfrac{4 -5}{-5 +8}\implies -\cfrac{1}{3} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7B%5CLARGE%20Line%20A%7D%7D%7B%28%5Cstackrel%7Bx_1%7D%7B-8%7D~%2C~%5Cstackrel%7By_1%7D%7B5%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B-5%7D~%2C~%5Cstackrel%7By_2%7D%7B4%7D%29%7D%20~%5Chfill%20%5Cstackrel%7Bslope%7D%7Bm%7D%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%20%7B%5Cstackrel%7By_2%7D%7B4%7D-%5Cstackrel%7By1%7D%7B5%7D%7D%7D%7B%5Cunderset%7Brun%7D%20%7B%5Cunderset%7Bx_2%7D%7B-5%7D-%5Cunderset%7Bx_1%7D%7B%28-8%29%7D%7D%7D%20%5Cimplies%20%5Ccfrac%7B4%20-5%7D%7B-5%20%2B8%7D%5Cimplies%20-%5Ccfrac%7B1%7D%7B3%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
keeping in mind that perpendicular lines have negative reciprocal slopes, and that parallel lines have equal slopes, well, those two slopes above aren't either, so since they're neither, and they're different, that means that lines A and B intersect.
Answer:
∠ABC = 46°
Step-by-step explanation:
DB and BC are of same length (radius), making it an isosceles triangle.
The base of the triangle is the same at 23°, a total of 46°.
180° - 46° = 134°
But we need ∠ABC, and since points DBA lie on the circumference, it's a straight line.
Therefore, 180° - 134° = 46°
Answer:
A)
Step-by-step explanation:
youjust have to do this:
100 miles-------------------2/3 hour
x-------------------------------3/3 hour or 1 hour
x=100x1/0.6666666667 2/3=0.6666666667
x= 150 miles
Answer:
x = 7
Step-by-step explanation:
123 = 17x + 4
123 - 4 = 17x
119 = 17x
119 / 17 = x
7 = x
