Answer:
Object should be placed at a distance, u = 7.8 cm
Given:
focal length of convex lens, F = 16.5 cm
magnification, m = 1.90
Solution:
Magnification of lens, m = -
where
u = object distance
v = image distance
Now,
1.90 = 
v = - 1.90u
To calculate the object distance, u by lens maker formula given by:
u = 7.8 cm
Object should be placed at a distance of 7.8 cm on the axis of the lens to get virtual and enlarged image.
Florence Griffith-Joyner recorded a time 10.61 seconds (wind reading +1.2) in the final at the 1988 U.S. Olympic Trials the wind reading for this race is not in doubt, and the performance should be the official IAAF women's 100-m world record
If you shine a light straight down onto that vector, then the length of its shadow on the x-axis is
x-component = 88 · cosine(13°)
x-component = 88 · (0.9744)
<em>x-component = 85.74</em>
Answer:
<h3><em>Flavonoids</em><em> </em><em>are</em><em> </em><em>a </em><em>diverse</em><em> </em><em>group</em><em> of</em><em> </em><em>phytonutrients</em><em> </em><em>(</em><em>plant</em><em> </em><em>chemical</em><em>)</em><em> </em><em>found</em><em> in</em><em> </em><em>almost</em><em> </em><em>all</em><em> </em><em>fruits</em><em> and</em><em> </em><em>vegetables. </em><em>Along</em><em> with</em><em> </em><em>carotenoids</em><em> </em><em>they</em><em> </em><em>are</em><em> </em><em>Responsible</em><em> for</em><em> the</em><em> </em><em>vivid</em><em> </em><em>color</em><em> </em><em>in </em><em>fruit</em><em> </em><em>and</em><em> vegetables</em><em>.</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em> </em><em>Like</em><em> </em><em>other</em><em> </em><em>phytonutrients</em><em> </em><em>flavonoids</em><em> </em><em>are</em><em> </em><em>powerful</em><em> </em><em>antioxidant</em><em> </em><em>with</em><em> </em><em>anti-inflammatory</em><em> </em><em>and</em><em> </em><em>immune</em><em> </em><em>system</em><em> </em><em>benefits</em><em>.</em></h3>
Had to look for the options and here is my answer.
The statement that is considered correct regarding a wave that is propagating along the pavement and girders of a suspension bridge is this: "t<span>he wave is mechanical, with particles vibrating in a direction that is perpendicular to that of the wave, forming compressions and rarefactions." Hope this helps.</span>