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klio [65]
3 years ago
13

Energy is required to produce a chemical change during

Chemistry
1 answer:
levacccp [35]3 years ago
5 0
<span>Energy is required to produce a chemical change during (2) electrolysis, given that it is the only stage which includes only a chemical change. The other options include physical changes as well.</span>
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What the reaction rates chart means​
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Reaction rates are usually expressed as the concentration of reactant consumed or the concentration of product formed per unit time. ... The graph shows the change in the number of A and B molecules in the reaction as a function of time over a 1 min period (bottom)
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What is the pH at the equivalence point in the titration of a 20.9 mL sample of a 0.357 M aqueous acetic acid solution with a 0.
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ph is the amount of toxins right

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(4.03 Q1) What is a substance which cannot be broken down into different
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An element

Elements are substances that cannot be broken down into simpler substances either by physical or chemical method.

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Is there any Chemical including in BIOGESIC?<br>Can you tell me if it was included?​
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This combination product contains 2 medications, acetaminophen and an antihistamine. Acetaminophen helps to reduce fever and/or mild to moderate pain (such as headache, backache, aches/pains due to muscle strain, cold, or flu).

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Read 2 more answers
1 mol super cooled liquid water transformed to solid ice at -10 oC under 1 atm pressure.
Arada [10]

Answer:

Explanation:

Given that:

number of moles of super cooled liquid water = 1

Melting enthalpy of ice = 6020 J/mol

Freezing point =0 °C = (0 + 273 K)= 273 K

The decrease in entropy of the system during freezing for 1 mol (i.e during transformation from liquid water to solid ice )  = - 6020 J/mol × 1 mol /273 K = -22.051 J/K

Entropy change during further cooling from 0 °C (273 K) to -10 °C (263 K)

\Delta \ S = \int\limits^{T_2}_{T_1}\dfrac{nC_p(s)dT}{T}

\Delta \ S = {nC_p(s)In \dfrac{T_2}{T_1}

\Delta \ S = {(1*37.7)In \dfrac{263}{273}

Δ S = -1.4 J/K

Total entropy change of the system = - 22.05 J/K - 1.4 J/K = - 23.45 J/K

Entropy change of universe = entropy change of the system+ entropy change of the surrounding

According to the second law of thermodynamics

Entropy change of universe  >0

SO,

Entropy change of the system + entropy change in the surrounding > 0

Entropy change in the surrounding > - entropy change of the system

Entropy change in the surrounding > - (- 23.53 J/K)

Entropy change in the surrounding > 23.53 J/K

b) Make some comments on entropy changes from the obtained data.

From the data obtained; we will realize that the entropy of the system decreases as cooling takes place when water is be convert to ice , randomness of these molecules reduces and as cooling proceeds , hence, entropy reduces more as well and the liberated heat will go into the surrounding due to this entropy of the surrounding increasing.

4 0
3 years ago
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