Given:
35.0 mL of acid with an unknown concentration
24.6 mL of 0.432 M base
Required:
Concentration of the acid
Solution:
M1V1 = M2V2
M1 (35.0 mL of acid)
= (0.432 M base) (24.6 mL
of base)
V1 = (0.432
M base) (24.6 mL of base) /
(35.0 mL of acid)
M1 = 0.304 M of acid
1 mol of any substance is made of 6.022 x 10²³ units.
When its 1 mol of a formula, its made of 6.022 x 10²³ formula units
Therefore if 6.022 x 10²³ formula units of CeI₃ make up 1 mol of CeI₃
Then 9.42 x 10²¹ formula units make up - 1/(6.022 x 10²³) x (9.42 x 10²¹) = 0.0156 mol of CeI₃
Therefore number of moles of CeI₃ - 0.0156 mol
Answer:
The values of n, p and q are 314, 0.12 and 0.88 respectively.
Explanation:
n is the number of subjects given a placebo. The value of n is 314.
p is the sample proportion of the subjects given a placebo that developed headaches. The value of is 12% = 0.12
q is the sample proportion of the subjects given a placebo that did not develop headaches. The value of q = 1 - p = 1 - 0.12 = 0.88
This is not a math question but I’ll help. The solute is what you are dissolving something in. The solvent is what is dissolved. So if you are dissolving juice crystals IN water the juice crystals would be the solvent and the water would be the solute
