In this case, this could be determined via the following equation for the determination of the absorbed heat by the aluminium, considering the heat capacity, the change in the temperature and the heated mass:
Aluminum does not undergo any phase change from 20.0°C to 100<span>.0°C, therefore we only consider sensible heat change, which is calculate as </span>q = mc(dT)q = (12.5 g)(0.125 cal/g-°C)(100 - 20)<span>°C = 125 cal </span> Therefore, 125 calories of heat are absorbed by the aluminum.
