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notsponge [240]
3 years ago
6

The specific heat of aluminum is 0.125 cal/g °C. If 12.5 grams of aluminum were heated from 20.0 °C to 100.0 °C, calories of hea

t energy would be absorbed by the aluminum.
Chemistry
2 answers:
WINSTONCH [101]3 years ago
7 0

Answer:

Q=125cal

Explanation:

Hello,

In this case, this could be determined via the following equation for the determination of the absorbed heat by the aluminium, considering the heat capacity, the change in the temperature and the heated mass:

Q=mCp\Delta T\\Q=mCp(T_2-T_1)\\Q=12.5g*0.125\frac{cal}{g*^oC}*(100.0-20.0)^oC\\ Q=125cal

Best regards.

klemol [59]3 years ago
4 0
Aluminum does not undergo any phase change from 20.0°C to 100<span>.0°C, therefore we only consider sensible heat change, which is calculate as
</span>q = mc(dT)q = (12.5 g)(0.125 cal/g-°C)(100 - 20)<span>°C = 125 cal
</span>
Therefore, 125 calories of heat are absorbed by the aluminum.
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1. 90.0 mL of distilled water is added to a 10.0mL sample of 0.150mol/L sodium
aniked [119]

Answer: dilute

Explanation:

A concentrated solution which is used to prepare solutions of lower concentrations by diluting it with addition of water.

A dilute solution is one which contains lower concentration.

Using Molarity equation:

M_1 =concentration of stock solution = 0.150 mol/L

V_1 = volume of stock solution = 10.0 ml

M_2 = concentration of dilute solution = ?

V_2 = volume of dilute solution = (10.0+90.0) ml = 100.0 ml

0.150\times 10.0=M_2\times 100.0

M_2=0.015mol/L

As the concentration is less than the original concentration, the solution is termed as dilute.

7 0
2 years ago
In the laboratory, a general chemistry student measured the pH of a 0.529 M aqueous solution of phenol (a weak acid), C6H5OH to
Artyom0805 [142]

Answer:

The dissociation constant of phenol from given information is 9.34\times 10^{-11}.

Explanation:

The measured pH of the solution = 5.153

C_6H_5OH\rightarrow C_6H_5O^-+H^+

Initially      c

At eq'm   c-x       x  x

The expression of dissociation constant is given as:

K_a=\frac{[C_6H_5O^-][H^+]}{[C_6H_5OOH]}

Concentration of phenoxide ions and hydrogen ions are equal to x.

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x=7.03\times 10^{-6} M

K_a=\frac{x\times x}{(c-x)}=\frac{x^2}{(c-x)}=\frac{(7.03\times 10^{-6} M)^2}{ 0.529 M-7.03\times 10^{-6} M}

K_a=9.34\times 10^{-11}

The dissociation constant of phenol from given information is 9.34\times 10^{-11}.

4 0
3 years ago
Here is my question..
OverLord2011 [107]
I would say 3.0 cause yeah yeah yeah yeah I’m iann Dior
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A & C.
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