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ryzh [129]
3 years ago
14

Honors Stoichiometry Activity Worksheet

Chemistry
1 answer:
vaieri [72.5K]3 years ago
6 0

Explanation: Here, we will be considering 1 cup is equal to 1 mol.

2 water + sugar + lemon juice → 4 lemonade

Moles of water present in 946.36 g of water=\frac{946.36 g}{236.59 g/mol}=4 mol

Moles of sugar present in 196.86 g of water=\frac{196.86 g}{225 g/mol}=0.8749 mol

Moles of lemon juice present in 193.37 g of water=\frac{193.37 g}{257.83 g/mol}=0.7499 mol

Moles of lemonade in 2050.25 g of water=\frac{2050.25 g}{719.42 g/mol}=2.8498 mol

As we can see that number of moles of lemon juice are limited.

So, we will consider the reaction will complete in accordance with moles of lemon juice.

1 mole lemon juice reacts with 2 mol of water,then 0.7499 mol of lemon juice will react with:

\frac{2}{1}\times 0.7499 mol = 1.4998 mol of water

Mass of water used =  1.4998 mol × 236.59 g/mol=354.8376 g

Water remained unused = 946.36 g - 354.8376 g =591.5223 g

1 mole lemon juice reacts with  mol of sugar,then 0.7499 mol of lemon juice will react with:

\frac{1}{1}\times 0.7499 mol = 0.7499 mol of water

Mass of sugar used =  0.7499 mol × 225 g/mol = 168.7275 g

Sugar remained unused = 196.86 g - 28.1325 g

1 mole of lemon juice gives 4 moles of lemonade.

Then 0.7499 mol of lemon juice will give:

\frac{4}{1}\times 0.7499 mol=2.996 mol of lemonade

Mass of lemonade obtained  = 2.996 mol × 719.42 g/mol = 2157.9722 g

Theoretical yield of lemonade = 2157.9722 g

Experimental yield of lemonade = 2050.25 g

Percentage yield of lemonade:

\frac{\text{Experimental yield}}{\text{theoretical yield}}\times 100

\frac{2050.25 g}{2157.9722 g}\times 100=95.00\%

The percentage yield of  lemonade is 95% and ingredient which remained unused were water and sugar.

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Balance Cr2O3+Mg -->Cr + MgO
fiasKO [112]

Balancing means there are equal amount of molecules on each side, both reactant and products. This is a method I like to do.

Under, I count how many molecules are in each side.

              Cr2O3+Mg -->Cr + MgO

Cr:              2                    1

O:                     3                            1

Mg:                         1                 1

Let's guess and make the number of oxygens equal on both sides.

              Cr2O3+Mg -->Cr + 3MgO

Cr:             2                    1

O:                      3                           3       EQUAL

Mg:                          1                   3

See what we did there? We multiplied the MgO on the products side by 3 so we can have 3 oxygens. Now let's multiply the Mg on the reactants by three so Mg AND O can be equal.

                Cr2O3+3Mg -->Cr + 3 MgO

Cr:              2                      1

O:                      3                               3        EQUAL

Mg:                         3                        3          EQUAL

Finally, we just need to multiply the loner Cr in the products side by two to make it equal for all elements.

                 Cr2O3+3Mg -->2Cr + 3 MgO

6 0
3 years ago
A change in temperature is called a temperature _______________?
RUDIKE [14]
A change in temperature is called a temperature change
3 0
3 years ago
The process that provides the sun with its energy
SashulF [63]

Answer:

Nuclear fusion

Explanation:

5 0
3 years ago
Carbon dioxide (CO2) is a gaseous compound. Calculate the percent composition of this compound. Answer using three significant f
Tamiku [17]

Carbon dioxide is a gaseous molecule made up of the elements, C and O. Each mole of carbon dioxide has one mole C and two mole oxygen atoms.

Molar mass of carbon dioxide (CO_{2})=(1 * 12.01\frac{g}{mol}) +(2* 16\frac{g}{mol})=44.01\frac{g}{mol}

Percentage by mass of carbon = \frac{(1*12.01\frac{g}{mol}) }{44.01\frac{g}{mol} } *100=27.3%

Percentage by mass of oxygen = \frac{(2*16\frac{g}{mol})}{44.01\frac{g}{mol} } *100=72.7%

Therefore C is 27.3 % and O is 72.7 % by mass in 1 mol CO_{2}

7 0
4 years ago
Read 2 more answers
What is the mass of 8.8 x 10^22 of magnesium
Romashka-Z-Leto [24]

Answer:

0.05

moles

Explanation:

In a mole of any substance, there exist

6.02⋅1023

units of that substance.

So here, we got:

3.01⋅1022Mg atoms⋅1mol6.02⋅1023M gatoms=0.05mol

3 0
3 years ago
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