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3 years ago

What is the name of CO2

Chemistry

2 answers:

aliya0001 [1]3 years ago

4 0

Answer:

Carbon Dioxide

Explanation:

fgiga [73]3 years ago

3 0

Answer: Carbon Dioxide

Explanation:

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A 55.0g sample of iron (III) filings is reacted with 23.8g of powdered sulfur (S8). How much iron (III) sulfide in moles would b

Margaret [11]

Answer:

0.744 mol

Explanation:

the balanced equation for the reaction is

8Fe + S₈ ---> 8FeS

molar ratio of Fe to S₈ is 8:1

number of moles of Fe - 55.0 g / 56 g/mol = 0.98 mol

number of moles of S - 23.8 g / 256 g/mol = 0.093 mol

if we are to assume that S₈ is the limiting reactant

if 1 mol of S₈ reacts with 8 mol of Fe

then 0.093 mol of S₈ reacts with - 8 x 0.093 mol = 0.744 mol of Fe

however there's 0.98 mol of Fe present but only 0.744 mol of Fe is needed

therefore Fe is in excess and S₈ is the limiting reagent

molar ratio of S₈ to FeS is 1:8

then 0.093 mol of S₈ reacts with - 8 x 0.093 = 0.744 mol of FeS

number of FeS moles produced is 0.744 mol

8 0

3 years ago

Read 2 more answers

Predict the products of hydrobromic acid, H B r , reacting with magnesium hydroxide, M g ( O H ) 2 . Select one or more:

Aliun [14]

Answer:

Magnesium bromide, MgBr2, and water, H2O.

Explanation:

Hello!

In this case, since HBr is an acid and Mg(OH)2 is a base, an acid-base reaction is undergone, by which a salt and water are produced as neutralization products:

$HBr+Mg(OH)_2\rightarrow MgBr_2+H_2O$

However, it need to be balanced since two bromine atoms are produced, therefore we write:

$2HBr+Mg(OH)_2\rightarrow MgBr_2+2H_2O$

Thus, the products are magnesium bromide, MgBr2, and water, H2O.

Best regards!

6 0

3 years ago

Type Calculations. Given the balanced equation: 2 Al + 3 H2SO4---> Al2(SO4)3 + 3 H2 Molar mass (g/mol): Al=26.98; H2SO4=98.08

Oxana [17]

Answer:

A. 1.88 mol H₂

B. 182 g Al₂(SO₄)₃

C. 54.8%

Explanation:

2 Al + 3 H₂SO₄ ⇒ Al₂(SO₄)₃ + 3 H₂

A. Convert grams of Al to moles. The molar mass is 26.98 g/mol.

(33.8 g)/(26.98 g/mol) = 1.253 mol Al

Use stoichiometry to convert moles of Al to moles of H₂. Looking at the equation, you can see that for every 2 mol of Al consumed, 3 moles of H₂ is produced. Use this relationship.

(1.253 mol Al) × (3 mol H₂)/(2 mol Al) = 1.879 mol H₂

You will produce 1.88 mol of H₂ gas.

B. Again, use stoichiometry. For every 3 moles of H₂SO₄ consumed, 1 mole of Al₂(SO₄)₃ is produced.

(1.60 mol H₂SO₄) × (1 mol Al₂(SO₄)₃/3 mol H₂SO₄) = 0.533 mol Al₂(SO₄)₃

Convert moles of Al₂(SO₄)₃ to grams. The molar mass is 342.15 g/mol.

(0.533 mol) × (342.15 g/mol) = 182.48 g Al₂(SO₄)₃

You will produce 182 g of Al₂(SO₄)₃.

C. Calculate percent yield by dividing the actual yield by the theoretical yield. Multiply by 100%.

(100.0/182.48) × 100% = 54.8%

The percent yield is 54.8%.

7 0

3 years ago

How many miles will a person run in a 10 kilometers race

marissa [1.9K]

Answer:

6.2 Miles!

Explanation:

4 0

3 years ago

I need help finding the formulas of these ionic compounds

AleksandrR [38]

Li3PO4
Cs3N
KL
BaF2
BaO
Reaction of. An acid and a base so it consists of an cation and anion so then you take the name of the anion and then the name of the cation take the atomic symbols and depending on the group it’s in add the numbers ? I think x

5 0

3 years ago