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3 years ago

Predict the products of hydrobromic acid, H B r , reacting with magnesium hydroxide, M g ( O H ) 2 . Select one or more:

Chemistry

1 answer:

Aliun [14]3 years ago

6 0

Answer:

Magnesium bromide, MgBr2, and water, H2O.

Explanation:

Hello!

In this case, since HBr is an acid and Mg(OH)2 is a base, an acid-base reaction is undergone, by which a salt and water are produced as neutralization products:

$HBr+Mg(OH)_2\rightarrow MgBr_2+H_2O$

However, it need to be balanced since two bromine atoms are produced, therefore we write:

$2HBr+Mg(OH)_2\rightarrow MgBr_2+2H_2O$

Thus, the products are magnesium bromide, MgBr2, and water, H2O.

Best regards!

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The solubility of oxygen gas in water at 40 ∘c is 1.0 mmol/l of solution. What is this concentration in units of mole fraction?

juin [17]

The formula for mole fraction is:

$mole fraction of solute = \frac{number of moles of solute}{total number of moles of solution}$ -(1)

The solubility of oxygen gas = 1.0 mmol/L (given)

1.0 mmol/L means 1.0 mmol are present in 1 L.

Converting mmol to mol:

$1.00 mmol\times \frac{1 mol}{1000 mmol} = 0.001 mol$

So, moles of oxygen = 0.001 mol

For moles of water:

1 L of water = 1000 mL of water

Since, the density of water is 1.0 g/mL.

$Density = \frac{mass}{volume}$

$Mass = 1.0 g/ml\times 1000 mL = 1000 g$

So, the mass of water is 1000 g.

Molar mass of water = 18 g/mol.

Number of moles of water = $\frac{1000 g}{18 g/mol} = 55.55 mol$

Substituting the values in formula (1):

$mole fraction = \frac{0.001}{55.55+0.001}$

$mole fraction = 1.8\times 10^{-5}$

Hence, the mole fraction is $1.8\times 10^{-5}$ .

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IRISSAK [1]

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