Answer:
8.31 × 10⁻²² kJ
Explanation:
Step 1: Given data
Energy required to remove one mole of electrons from the atoms at the surface of a solid metal: 500 kJ/mol e⁻
Step 2: Calculate how much energy does it take to remove a single electron from an atom at the surface of this solid metal
We will use Avogadro's number: there are 6.02 × 10²³ electrons in 1 mole of electrons.
500 kJ/mol e⁻ × 1 mol e⁻/6.02 × 10²³ e⁻ = 8.31 × 10⁻²² kJ/e⁻
Called a(n) convection current
Answer: The heat of combustion per mole for acetylene is 227.7 kJ/mol.
Explanation:
The combustion equation of acetylene is as follows.

Formula to calculate enthalpy of formation for a reaction is as follows.
![\Delta H^{o}_{rxn} = \sum \Delta H_{products} - \sum \Delta H_{reactants}\\\Delta H^{o}_{rxn} = [2\Delta H^{o}_{f}(CO_{2}) + \Delta H^{o}_{f} (H_{2}O)] - [\Delta H^{o}_{f}(C_{2}H_{2}) + \frac{5}{2} \Delta H^{o}_{f} O_{2}]\\-1299.5 = 2(-393.5) + (-285.8) - \Delta H^{o}_{f} (C_{2}H_{2})\\\Delta H^{o}_{f} (C_{2}H_{2}) = 227.7 kJ/mol](https://tex.z-dn.net/?f=%5CDelta%20H%5E%7Bo%7D_%7Brxn%7D%20%3D%20%5Csum%20%5CDelta%20H_%7Bproducts%7D%20-%20%5Csum%20%5CDelta%20H_%7Breactants%7D%5C%5C%5CDelta%20H%5E%7Bo%7D_%7Brxn%7D%20%3D%20%5B2%5CDelta%20H%5E%7Bo%7D_%7Bf%7D%28CO_%7B2%7D%29%20%2B%20%5CDelta%20H%5E%7Bo%7D_%7Bf%7D%20%28H_%7B2%7DO%29%5D%20-%20%5B%5CDelta%20H%5E%7Bo%7D_%7Bf%7D%28C_%7B2%7DH_%7B2%7D%29%20%2B%20%5Cfrac%7B5%7D%7B2%7D%20%5CDelta%20H%5E%7Bo%7D_%7Bf%7D%20O_%7B2%7D%5D%5C%5C-1299.5%20%3D%202%28-393.5%29%20%2B%20%28-285.8%29%20-%20%5CDelta%20H%5E%7Bo%7D_%7Bf%7D%20%28C_%7B2%7DH_%7B2%7D%29%5C%5C%5CDelta%20H%5E%7Bo%7D_%7Bf%7D%20%28C_%7B2%7DH_%7B2%7D%29%20%3D%20227.7%20kJ%2Fmol)
Thus, we can conclude that heat of combustion per mole for acetylene is 227.7 kJ/mol.
Answer:
Answer is explained in the explanation section below.
Explanation:
Solution:
Note: This question is incomplete and lacks very important data to solve this question. But I have found the similar question which shows the profiles about which question discusses. Using the data from that question, I have solved the question.
a) We need to find the major species from A to F.
Major Species at A:
1. 
Major Species at B:
1. 
2. 
Major Species at C:
1. 
Major Species at D:
1. 
2. 
Major Species at E:
1. 
Major Species at F:
1. 
b) pH calculation:
At Halfway point B:
pH = pK
+ log[
]/[H
]
pH = pK
= 6.35
Similarly, at halfway point D.
At point D,
pH = pK
+ log [H
]/[H2
]
pH = pK
= 10.33