<span>How many mols is 1433.6 iron atoms? my calculations are 2.380548514178884521</span>
Explanation:
Number of moles(n)=Number of atoms(N)/Avogadro's constant.
Avogadro's constant=6.02×10²³
so we have
n=9.05×10²³/6.02×10²³
n=1.0503moles.
n=mass/molar mass
1.0503=mass/28
mass=1.0503×28
mass=29.4084g
Answer:
Volume of water at this temperature is 27.2 mL
Explanation:
We know that 
Here density of water is 0.992 g/mL
Here mass of water is 27.0 g
So 
= 
= 27.2 mL
Remember one thing controlled variables is something. In an experiment that you like and you want to remain the same in order for the science experiment to be good
Answer:
n = 0.271 moles
Explanation:
Given that,
Volume of container, V = 14 L
Pressure of Nitrogen gas, P = 375 torr
Temperature. T = 37°C=37+273=310°C
We need to find the number of moles of nitrogen in the container. Using gas equation,
PV = nRT
R is gas constant, R = 0.082 L-atm/mol-K
Since, 1 atm=760 torr
375 torr = 0.493 atm
Now,

So, there are 0.271 moles of Nitrogen in the container.