You need to use q = mc(delta t)
<span>Solve for c: </span>
<span>c = q / m(delta t) </span>
<span>q = 55.o J </span>
<span>m = 11.0 g </span>
<span>delta t = 24.5 - 13.0 = 11.5 deg C </span>
<span>c = 55 J / 11.0 g)(11.5 C) </span>
<span>c = 0.435 J/ g C</span>
You have to use this knwoledge:
1) The superscript number on the left of the symbol is the mass number (A)
2) The underscript number on the left of the symbol is the atomic number (Z)
3) The atomic number, Z, is the number of protons of the atom.
4) The number of electrons of an atoms is equal to the number of protons.
5) The mass number, A is equal to the number of neutrons, N, plus the number of protons, Z, i.e. A = N + Z, from which you obtain N = A - Z
Now I am going to apply above rules to solve the three cases for you.
I will use other notation just because the editor does not permit to place superscripts and underscripts on the left of the symbol.
a) 62 Cu 29 and 62 Zn 39
62 Cu 29:
Z = 29 = number of protons
A = 62 = N + Z => N = 62 - Z = 62 - 29 = 33
Number of electrons = number of protons = 29
62 Zn 39:
Z = 39 = number of protons
A = 62 = N + Z => N = 62 - Z = 62 - 39 = 23
Number of electrons = number of protons = 39
Answers:
protons are not equal
neutrons are not equal
electrons are not equal.
b) 40Ar18 and 41K19
40Ar18:
Z = 18 = number of protons
A = 40 = N + Z => N = 40 - 18 = 22 = number of neutrons
number of electrons = number of protons 18
41K19:
Z = 19 = number of protons
A = 41 = N + Z> N = 41 - 19 = 22
number of electrons = number of protons = 19
Answers:
protons are not equal
neutrons are equal
electrons are not equal
c) 14N7 and 15N7
14N7:
Z = 7 = number of protons
A = 14 => N = 14 - 7 = 7 = number of neutrons
number of elecfrons = number of protons = 7
15N7:
Z = 7 = number of protons
A = 15 => N = 15 - 7 = 8 = number of neutrons
number of electrons = number of protons = 7
Answers:
protons are equal
neutrons are not equal
electrons are equal
Answer:
Explanation:
By Ideal Gas Law, P1*V1 / T1 = P2*V2 / T2
So new pressure = (P1*V1 / T1) / (V2 / T2)
= P1*V1*T2 / T1*V2
= 800*3.6*298 / 250*1.8
= 1907.2 mmHg
Answer:
Eqv Pt pH = 8.73
Explanation:
HOAc + NaOH => NaOAc + H₂O
50ml(0.10M HOAc) + 50ml(0.10M NaOH) => 100ml(0.05M NaOAc) + H₂O
For neutralized system, 100ml of 0.05M NaOAc remains
NaOAc => Na⁺ + OAc⁻
Na⁺ + H₂O => No Rxn
OAc⁻ + H₂O => HOAc + OH⁻
C(i) 0.05M ----- 0M 0M
ΔC -x ----- +x +x
C(f) 0.05-x
≅ 0.05M ----- x x
Kb = Kw/Ka = [HOAc][OH⁻]/[OAc⁻] = 1 X 10⁻¹⁴/1.7 X 10⁻⁵ = (x)(x)/(0.05M)
=> x = [OH⁻] = SqrRt(0.05 x 10⁻¹⁴/1.7 x 10⁻⁵) = 5.42 x 10⁻⁶M
=> pOH = -log[OH⁻] = -log(5.42 x 10⁻⁶) = 5.27
pH + pOH = 14 => pH = 14 - pOH = 14 - 5.27 = 8.73 Eqv Pt pH
Answer:
A
Explanation:c C B D are just wrong hope this helps god bless