Answer:
Step-by-step explanation:
not sure sorry ask a parent
The answer for the first blank is 36 and the answer for the second blank is 97.
To complete the square, we first take half of the value of b. The value of b in this equation is -12; -12/2 = -6.
Next we square the value we just got: (-6)² = 36.
This is what we add to both sides of the equation, giving us:
x²-12x+36=61+36
Combining like terms on the right, we have
x²-12x+36=97
Answer:
Step-by-step explanation:
It can be convenient to compute the length of the hypotenuse of this triangle (AC). The Pythagorean theorem tells you ...
AC^2 = AB^2 + CB^2
AC^2 = 4^2 + 3^2 = 16 + 9 = 25
AC = √25 = 5
The altitude divides ∆ABC into similar triangles ∆AHB and ∆BHC. The scale factor for ∆AHB is ...
scale factor ∆ABC to ∆AHB = AB/AC = 4/5 = 0.8
And the scale factor to ∆BHC is ...
scale factor ∆ABC to ∆BHC = BC/AC = 3/5 = 0.6
Then the side AH is 0.8·AB = 0.8·4 = 3.2
And the side CH is 0.6·BC = 0.6·3 = 1.8
These two side lengths should add to the length AC = 5, and they do.
The remaining side BH can be found from either scale factor:
BH = AB·0.6 = BC·0.8 = 4·0.6 = 3·0.8 = 2.4
_____
The sides of interest are ...
AH = 3.2
CH = 1.8
BH = 2.4
Answer:
a) 1/27
b) 2/91
Step-by-step explanation:
A bag contains 10 red marbles and 5 blue marbles (15 marbles in total). You randomly select 3 marbles from the bag.
a) You replace each marble before selecting the next one.
The probability of selecting one blue marble is
![\dfrac{5}{15}=\dfrac{1}{3},](https://tex.z-dn.net/?f=%5Cdfrac%7B5%7D%7B15%7D%3D%5Cdfrac%7B1%7D%7B3%7D%2C)
then the probability that all 3 marbles are blue is
![\dfrac{1}{3}\times \dfrac{1}{3}\times \dfrac{1}{3}=\dfrac{1}{27}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B3%7D%5Ctimes%20%5Cdfrac%7B1%7D%7B3%7D%5Ctimes%20%5Cdfrac%7B1%7D%7B3%7D%3D%5Cdfrac%7B1%7D%7B27%7D)
b) You do not replace each marble before selecting the next one. Each time the number of blue marbles decreases by 1 and the total number of marbles decreases by 1 too. So the probability that all 3 marbles are blue is
![\dfrac{5}{15}\times \dfrac{4}{14}\times \dfrac{3}{13}=\dfrac{2}{91}](https://tex.z-dn.net/?f=%5Cdfrac%7B5%7D%7B15%7D%5Ctimes%20%5Cdfrac%7B4%7D%7B14%7D%5Ctimes%20%5Cdfrac%7B3%7D%7B13%7D%3D%5Cdfrac%7B2%7D%7B91%7D)