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Marta_Voda [28]
4 years ago
7

The depth of the liquid is 10 cm and the radius of the cylinder is 3.0 cm. The weight of

Physics
1 answer:
denpristay [2]4 years ago
8 0
By using the formula density(p)= mass(kg)/volume(m^3) and gravitational acceleration (g)
Mass=2.5N/9.8m/s^2=0.26kg
Volume=0.1x 0.03^2 x3.142=0.009m^3
Density=28.89kg/m^-3
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Pls help me this is being timed.
GrogVix [38]

Answer:

Increase air resistance

Explanation:

Gravity forces the parachute down but air resistance pushing up on the flat surface of the parachute causes it to fall slower to the ground.

5 0
3 years ago
Which of the following is the correct definition of conduction? A. the transfer of heat by currents within a liquid or gas B. th
dolphi86 [110]
I believe it's B. the transmission of heat across matter
6 0
3 years ago
Read 2 more answers
When an electron de-excites from the third quantum level to the second, and then to the ground state, two photons are emitted. T
Leokris [45]

Answer:

ground state

Explanation:

  Lets take  

n=3 ,n=2 ,n=1 are the energy level.

Energy level n=1 is the ground energy level.

The energy from 3 to 1 = hν

The energy from 3 to 2 = hν₁

The energy from 2 to 1 = hν₂

We can say that

hν = hν₁ +  hν₂

If the electron were de-excitation from the third level to ground level then the sum of emitted frequency will be equal to the frequency of a single electron.

Therefore the answer is ground state.

3 0
3 years ago
A thin cylindrical shell is released from rest and rolls without slipping down an inclined ramp that makes an angle of 30° with
NNADVOKAT [17]

Answer: 1.59 sec

Explanation:

The kinetic energy contained in the rotation of the cylinder is 1/2 m v^2

The kinetic energy of translation is also 1/2 m v^2

so the total energy is m v^2

The force applied is mg sin (theta)

= m x 9.8 x 1/2

= 4.9 m

Now equate

F x d = m v^2

4.9 m x 3.1 = m v^2

v^2 = 4.9 x 3.1

v = sqrt(4.9 x 3.1) = 3.9 m/s

Acceleration.

V^2 = 2 a s

4.9 x 3.1 = 2 x a x 3.1

4.9 = 2 a

a = 2.45 m/s^2

Time

T = v/a

= 3.9/2.45

= 1.59 sec

6 0
4 years ago
What is the concentration of molecular oxygen (O2) in mol/L on a June day in Toronto when atmospheric pressure is 1.0 atm and th
saveliy_v [14]

Answer:

The concentration of mole evil at oxygen on that day is 0.00858 mol/L

Explanation:

Here, we want to calculate the concentration of molecular oxygen

The pressure on that day is 1.0 atm

Since oxygen is at a concentration of 21%, the pressure of oxygen will be 21/100 * 1 = 0.21 atm

Now let’s calculate the concentration;

From Ideal gas law;

PV = nRT

This can be written as;

P/RT = n/V

The term n/V refers to concentration;

Let’s make substitutions now;

P = pressure = 0.21 atm

R = molar gas constant = 0.0821 L•atm/mol•k

T = temperature = 25 = 25 + 273.15 = 298.15 K

Substituting these values, we have;

n/V = C = 0.21/(0.0821 * 298.15) = 0.00858 mol/L

6 0
3 years ago
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