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Marta_Voda [28]
3 years ago
7

The depth of the liquid is 10 cm and the radius of the cylinder is 3.0 cm. The weight of

Physics
1 answer:
denpristay [2]3 years ago
8 0
By using the formula density(p)= mass(kg)/volume(m^3) and gravitational acceleration (g)
Mass=2.5N/9.8m/s^2=0.26kg
Volume=0.1x 0.03^2 x3.142=0.009m^3
Density=28.89kg/m^-3
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Your teacher (175kg) and the lab (15kg) are 2m apart. What is the gravitational force between them? Draw a FBD, and label
Pachacha [2.7K]
The gravitational force between two objects is given by
F=G \frac{m_1 m_2 }{r^2}
where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is the separation between the two objects

In this problem, m_1 = 175 kg, m_2 =15 kg and r=2 m, therefore the gravitational force between the two objects is
F=(6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2}) \frac{(175 kg)(15 kg)}{(2m)^2}=4.38 \cdot10^{-8} N
7 0
3 years ago
While on a moving elevator during a certain perfod or time, Frank's apparent weight is 620 N. If Frank's mass is 70 kg, what is
MakcuM [25]

Answer:

0.94 m/s^2 downwards

Explanation:

m = 70 kg, m g = 70 x 9.8 = 686 N

R = 620 N

Let the acceleration be a, as the apparent weight decreases so the elevator is moving downwards with an acceleration a.

mg - R = ma

686 - 620 = 70 x a

a = 0.94 m/s^2

7 0
3 years ago
Two teams of nine members each engage in tug-of-war. Each of the first team's members has an average mass of 68 kg and exerts an
diamong [38]

Answer:

(a) Acceleration  = 0.1063 m/s^2      (Second team wins)

(b) Tension in rope = 65.106 N

Explanation:

Total mass of first team = 68 * 9 = 612 kg

Total force of first team = 1350 * 9 = 12150 N

Total mass of second team = 73 * 9 = 657 kg

Total force of seconds team = 1365 * 9 = 12285 N

Difference in force = 12285 - 12150 = 135 N   (towards the second team as it has more force)

(a) For acceleration we get:

F = m * a

135 = (mass of both teams) * a

a = 135 / (612 + 657)

acceleration  = 0.1063 m/s^2      (Second team wins)

(b) Since we know the acceleration of the first team (pulling being pulled towards the second team at an acceleration of 0.1063 m/s^2) , we can find out the force required to move them:

Force required for first team = mass of first team * acceleration

Force required = 612 * 0.1063

Force required = 65.106 N

This is the force exerted on the first team through the rope, so the tension in the rope will also be 65.106 N.

7 0
4 years ago
Nanotechnology is currently used in electronics for
VMariaS [17]

Answer:

data storage, OLEDS, and wires

Explanation:

3 0
3 years ago
Which has a greater momentum? A 1200kg car traveling at 30m/s or a 2000kg truck traveling at 20m/s
Fittoniya [83]

the formula for momentum is velocity times mass

car :

1200 x 30 = 36000

truck:

2000 x 20 = 40000

Ans : truck has a greater momentum

7 0
3 years ago
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