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3 years ago

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1 answer:

aniked [119]3 years ago

7 0

Answer:

kinetic energy

Explanation:

kinetic energy is the type of energy which makes an object move from it fixed point to another

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resolve the position vector A of thd car (measured from fixed point O) into components parallel to OB and OC

forsale [732]

Catalysts are used in the oil industry to increase octane ratings in gasoline. Octane ratings tell how much fuel has to be compressed to promote better fuel ignition in some cars. The catalytic effect that would be most beneficial for the oil industry is that more products can be formed from a given amount of material.

7 0

3 years ago

A student in an undergraduate physics lab is studying Archimede's principle of bouyancy. The student is given a brass cylinder a

Readme [11.4K]

Answer:

V = 0.3724 m³

T = 27.836 N

Explanation:

Given :

m = 3.21 kg , W= 3.21 * 9.81 m / s² = 31.4901 N

ρ = 8.62 g / cm ³ = 8620 kg / m³

V = m / ρ = 3.21 kg / 8620 kg / m³

V = 0.3724 m³

when submerged the weight of brass cylinder is equal to the tension in string:

F = (0.3724m³) * (1000 kg / m³) * (9.81 m/s²²) = 3.653 ≈ 3.65 N

T = 31.4901 N - 3.65 N

T = 27.836 N

3 0

3 years ago

When objects are charged by _______, they do not need to touch each other.

Deffense [45]

C because conduction you don’t need to touch anything

6 0

3 years ago

A man jumps from a 45 m cliff into a large body of water. How long will he fall before he enters the wate

julia-pushkina [17]

Answer:

about 2.5 seconds depending on if he jumps up and out or if he jumps out.

Explanation:

7 0

2 years ago

As an admirer of Thomas Young, you perform a double-slit experiment in his honor. You set your slits 1.15 mm apart and position

Artist 52 [7]

Answer:

The distance of the first bright fringe is given as $Y_C = 1.22 *10^{-3}m$

The distance of the second dark fringe from the central bright fringe is given as $Y_D = 0.00192 \ m$

Explanation:

From the question we are told that

The slit separation distance is $d = 1.15 mm = \frac{1.15}{1000} =0.00115 m$

The distance of the slit from the screen is $D = 3.23 m$

The wavelength is $\lambda = 633 nm$

For constructive interference to occur the distance between the two slit is mathematically represented as

$Y_C =\frac{m \lambda D}{d}$

Where m is the order of the fringe which has a value of 1 for first bright fringe

Substituting values

$Y_C = \frac{1 * 633 *0^{-9} * 3.23}{0.00115}$

$Y_C = 1.22 *10^{-3}m$

For destructive interference to occur the distance between the two slit is mathematically represented as

$Y_D = [n + \frac{1}{2} ] \frac{\lambda D}{d}$

m = 2

so the formula to get the dark fringe is $n = \frac{1}{2} * 1$

$n=1$

Now substituting values

$Y_D = [ 1 + \frac{1}{2} ] * \frac{633 *10^{-9} * 3.23 }{0.00115}$

$Y_D =1.5 * \frac{633 *10^{-9} * 3.23 }{0.00115}$

$Y_D = 0.00192 \ m$

4 0

3 years ago