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White raven [17]

4 years ago

10

Study the flowchart. The flowchart shows you all the steps to building a good working model of something. What steps lead to mak

ing improvements to a model?

1 answer:

inessss [21]4 years ago

7 0

testing the model and analyzing the results of the tests

Explanation:

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I need these for test corrections that are due tomorrow please :)

Ivahew [28]

That would be position Y, as the northern hemisphere is tilted away from the sun.

6 0

4 years ago

Needing help with this please

Gemiola [76]

Answer:

So A we cant sadly do because we cant draw. B is going to be kinetic. Thats because static friction means it stays in one place, for kinetic it means moving. So it will be 0.05 as the coefficient of the friction. Sadly, I cannot calculate C. You will have to use trigonemetry but I cannot fit that big an explanation.

Answer to A: the free body diagram would be the ski things inclined with gravity, friction, and air resistance. I except you know which directions

Answer to B: Kinetic friction is the answer.

Answer to C: Find on own, I cannot write super big explanations - use trigonometry.

6 0

3 years ago

The number of mushrooms needed by a pizza restaurant is given by the

kupik [55]

Answer: 24

Explanation:

Given the following equation:

$g=3n$

Where $g$ is the number of mushrooms in a pizza and $n$ the number of pizzas.

If we know the restaurant will make 8 pizzas ( $n=8$ ), then:

$g=3(8)$

$g=24$ This is the needed number of mushrooms for 8 pizzas

8 0

3 years ago

Two electrons are initially at rest separated by a distance of 2nm. At time t=0, they start to move apart due to Coulombic repul

Gnom [1K]

Answer:

$t=2.5\times 10^{-14}\ s$

Explanation:

We know that charge on electron

$q=1.6\times 10^{-19}\ C$

r= 2 nm

We know that force between two charge given

$F=K\dfrac{Q_1Q_2}{r^2}$

Now by putting the value

$F=9\times10^9\dfrac{1.6\times 10^{-19}\times 1.6\times 10^{-19}}{(2\times 10^{-9})^2}$

$F=5.67\times 10^{-11}\ N$

We know that mass of electron

The mass of electron

$m=9.1\times 10^{-31}\ kg$

F= m a

a= Acceleration of electron

a= F/m

$a=\dfrac{5.67\times 10^{-11}}{9.1\times 10^{-31}}\ m/s^2$

$a=6.2\times 10^{19} m/s^2$

$S=ut+\dfrac{1}{2}at^2$

initial velocity given that zero ,u=0

$20\times 10^{-9}=\dfrac{1}{2}\times 6.2\times 10^{19} t^2$

$t=\sqrt {\dfrac{40\times 10^{-9}}{6.2\times 10^{19}}}$

$t=2.5\times 10^{-14}\ s$

3 0

4 years ago

How will the gravitational force on a piece of the surface of the star (m1) by the mass of the rest of the star (m2) (effectivel

kiruha [24]

Answer:

Option B

Explanation:

Gravitational force is a force that attracts two bodies (with a mass) towards each other. If an object has a higher mass, the gravitational pull will be greater.

According to Newton’s inverse square law:

<em>"The gravitational force is inversely proportional to the square of the distance between two bodies."</em>

About this question, the greater the distance between two gravitating bodies, the weaker is the gravitational force between them.

6 0

3 years ago