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sammy [17]
3 years ago
11

How will the gravitational force on a piece of the surface of the star (m1) by the mass of the rest of the star (m2) (effectivel

y located at a point at the center of the star) compare between the AGB and main-sequence phases of a particular star, assuming its mass stays the same?A. The surface will feel a stronger gravitational force during the AGB phase because the star is larger.
B. The surface will feel a weaker gravitational force during the AGB phase because it is farther from the center of the star.
C. The surface will feel the same gravitational force during both phases.
Physics
1 answer:
kiruha [24]3 years ago
6 0

Answer:

Option B

Explanation:

Gravitational force is a force that attracts two bodies (with a mass) towards each other. If an object has a higher mass, the gravitational pull will be greater.

According to Newton’s inverse square law:

<em>"The gravitational force is inversely proportional to the square of the distance between two bodies."</em>

About this question, the greater the distance between two gravitating bodies, the weaker is the gravitational force between them.

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