Answer
Time period T = 1.50 s
time t = 40 s
r = 6.2 m
a)
Angular speed ω = 2π/T
=
= 4.189 rad/s
Angular acceleration α =
=
= 0.105 rad/s²
Tangential acceleration a = r α = 6.2 x 0.105 = 0.651 m/s²
b)The maximum speed.
v = 2πr/T
=
= 25.97 m/s
So centripetal acceleration.
a =
=
= 108.781 m/s^2
= 11.1 g
in combination with the gravitation acceleration.
There are 2 electrons generated from the oxidation of one water molecule.
<h3>Describe photooxidation.</h3>The process of a substance interacting with oxygen or losing electrons from chemical species under the influence of light is known as photooxidation. Photooxidation happens in plants when there is environmental stress. It is called photooxidative stress as a result. Reactive oxygen species are produced by the absorption of excess excitation energy in plant tissues. Chloroplasts are harmed by the accumulation of these reactive oxygen species, which is a damaging process in plants. High-intensity light and little are the two conditions that cause this photooxidative stress to occur most frequently. It is a procedure that requires light. Photorespiration in
plants guards against photooxidation.
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Answer:
(I). The angular acceleration and number of revolution are -2.5 rad/s² and 500 rad.
(II). The torque is 84.87 N-m.
Explanation:
Given that,
Initial spinning = 50.0 rad/s
Time = 20.0
Distance = 2.5 m
Mass of pole = 4 kg
Angle = 60°
We need to calculate the angular acceleration
Using formula of angular velocity
The angular acceleration is -2.5 rad/s²
We need to calculate the number of revolution
Using angular equation of motion
Put the value into the formula
The number of revolution is 500 rad.
(II). We need to calculate the torque
Using formula of torque
Put the value into the formula
Hence, (I). The angular acceleration and number of revolution are -2.5 rad/s² and 500 rad.
(II). The torque is 84.87 N-m.