Answer:
Height of mirror 0.075 m
width of mirror 0.325 m
Explanation:
given data
wide = 1.3 m
high = 0.30 m
driver’s eyes = 0.50 m
rear window = 1.50 m
solution
we take here height / width of the mirror is
height / width =
.................1
and
height /width of the window is
height /width =
.................2
and
distance of eye / window by the mirror is
distance of eye / window =
.................3
so here
θ = θi = θr ....................4
and tanθ for vertical is
tanθ =
tanθ =
....................5
so
h =
....................6
put here value and we get
h = 0.075 m
and
when we take here tanθ for horizontal than it will be
tanθ =
tanθ =
.......................7
so
....................8
put here value and we get
w = 0.325 m
Explanation:
Answer. Due to stroking the piece of steel, the domains which are randomly arranged get aligned in the direction of stroking by the magnet. Due to this alignment of the domains, the piece of steel attains magnetic properties.
Answer:
Part A the answer is the dielectric constant.
Part B Mica- mylar- paper- quartz
Explanation:
The capacity of a capacitor is given by
C = ε ε₀ A / d
Where the dielectric constant (ε) is the value of the material between the plates of the capacitor, we see that as if value increases the capacity also increases.
Another magnitude that we must take into account that the maximum working voltage, the greater the safer is the capacitor
the flexibility of the material must also be taken into account
Part A the answer is the dielectric constant.
Pate B order the materials from best to worst
Mica. The best ever
Mylar Flexible
Paper Low capacity, low working voltage, flexible
Quartz high dielectric, but brittle
A) We differentiate the expression for velocity to obtain an expression for acceleration:
v(t) = 1 - sin(2πt)
dv/dt = -2πcos(2πt)
a = -2πcos(2πt)
b) Any value of t can be plugged in as long as it is greater than or equal to 0.
c) we integrate the expression of velocity to find an expression for displacement:
∫v(t) dt = ∫ 1 - sin(2πt) dt
x(t) = t + cos(2πt)/2π + c
x(0) = 0
0 = = + cos(0)/2π + c
c = -1/2π
x(t) = t + cos(2πt)/2π -1/2π