Answer:
Explanation:
<u>1) Data:</u>
a) n = ?
b) V = 50.0 dm³ = 50.0 liter
c) p = 100.0 kPa
d) T = 50 °C
<u>2) Physical law:</u>
<u>3) Constants:</u>
- R = 0.08206 atm-liter / K-mol
<u>4) Unit conversions:</u>
- T = 50 + 273.15 K = 323.15 K
- P = 100.0 kPa × (1 amt /101,325 kPa) = 0.9869 atm
<u>5) Solution:</u>
- n = 0.9869 atm × 50.0 liter / (0.08206 atm-liter /K-mol × 323.15 K)
Chromosomes abnormalities often happen due to one or more of these:
Errors during of sex cells (meiosis)
Errors during of other cells(mitosis)
Substances that causes birth defects (teratogens)
The correct response would be A. The slowest step that determines the speed(rate) of the overall reaction.
Answer:
1.03 grams of hydrogen is produced from 12.5 g of Mg reacting with hydrochloric acid.
Explanation:
The balanced reaction is:
Mg+ 2 HCl → MgCl₂ + H₂
By stoichiometry of the reaction, the following amounts of moles of each compound participate in the reaction:
- Mg: 1 mole
- HCl: 2 moles
- MgCl₂: 1 mole
- H₂: 1 mole
Being the molar mass of each compound:
- Mg: 24.31 g/mole
- HCl: 36.45 g/mole
- MgCl₂: 95.21 g/mole
- H₂: 2 g/mole
By reaction stoichiometry, the following mass amounts of each compound participate in the reaction:
- Mg: 1 mole* 24.31 g/mole= 24.31 g
- HCl: 2 moles* 36.45 g/mole= 72.9 g
- MgCl₂: 1 mole* 95.21 g/mole= 95.21 g
- H₂: 1 mole* 2 g/mole= 2 g
Then you can apply the following rule of three: if by stoichiometry 24.31 grams of Mg produces 2 grams of H₂, 12.5 grams of Mg produces how much mass of H₂?
mass of H₂= 1.03 grams
<u><em>1.03 grams of hydrogen is produced from 12.5 g of Mg reacting with hydrochloric acid.</em></u>
Answer:
t = 1862 s
Explanation:
To do this, we need first to determine the theorical detention time, which can be determined with the following expression:
t₀ = ∀/Q (1)
Where:
t₀: detention time
∀: Volume of the fluid in the reactor
Q: Flow rate in the reactor
With this time, we must use the following expression to determine the time that the workers will take to vent the tank:
C = C₀ e^(-t/t₀) (2)
From here, we must solve for time t, and the expression will be:
t = ln(C₀/C) * t₀ (3)
Now that we know the expression to use, let's solve for t. Using (1) to determine the detention time, ∀ is 1900 m³, and Q is 2.35 m³/s so:
t₀ = 1900 / 2.35 = 808.51 s
Now, let's solve for the time t. C will be 0.0015 mg/L (or 1.5 mg/m³ cause in 1 m³ we have 1000 L) and C₀ 15 mg/m³:
t = ln(15/1.5) * 808.51
<h2>
t = 1861.66 s or simply 1862 s</h2><h2>
</h2>
Hope this helps
