The reaction equation may be written as:
2Li + 2H₂O → 2LiOH + H₂
A single mole of gas occupies 22,400 ml of gas at STP. Therefore, the moles of hydrogen gas are
75.5 / 22,400 = 0.0034 mol
According to the equation, the moles of lithium are twice that of hydrogen gas; thus,
0.0034 x 2 = 0.0068 mol
The mass of lithium is given by:
mass = moles x atomic mass
mass = 0.0068 x 6.9
mass = 0.047 grams
Answer:
N is single bonded to R, and single bonded twice to H.
Explanation:
The functional group present in an amine will not be complete without mentioning the nitrogen group present in the compound.
Amines are organic compounds that show appreciable basicity. They are regarded as the derivatives of ammonia where one or two or the three hydrogen atoms has/have been replaced been replaced by alkyl or aryl groups.
- Amines are classified as primary, secondary or tertiary based on the number of substituted hydrogen atoms they carry.
- The nitrogen bonded to the R - aryl group and bonded to hydrogen is a good description of the functional group.
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crystallize from magma
precipitate from a solution reaction of hot mixture with water and a dissolved substance</span>
Answer:
0.004522 moles of hydrogen peroxide molecules are present.
Explanation:
Mass by mass percentage of hydrogen peroxide solution = w/w% = 3%
Mass of the solution , m= 5.125 g
Mass of the hydrogen peroxide = x
Mass of hydregn pervade in the solution = 0.15375 g
Moles of hydregn pervade in the solution :
0.004522 moles of hydrogen peroxide molecules are present.
Answer: The concentration of 
ions in vinegar is 0.001 M.
Explanation:
Given: pH = 3.0
pH is the negative logarithm of concentration of hydrogen ion.
The expression for pH is as follows.
![pH = - log [H^{+}]](https://tex.z-dn.net/?f=pH%20%3D%20-%20log%20%5BH%5E%7B%2B%7D%5D)
Substitute the value into above expression as follows.
![pH = - log [H^{+}]\\3.0 = - log [H^{+}]\\conc. of H^{+} = antilog (- 3.0)\\= 0.001 M](https://tex.z-dn.net/?f=pH%20%3D%20-%20log%20%5BH%5E%7B%2B%7D%5D%5C%5C3.0%20%3D%20-%20log%20%5BH%5E%7B%2B%7D%5D%5C%5Cconc.%20of%20H%5E%7B%2B%7D%20%3D%20antilog%20%28-%203.0%29%5C%5C%3D%200.001%20M)
Thus, we can conclude that the concentration of ions in vinegar is 0.001 M.
