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Hey I think it is going to be 0986 moles. Cuz we can see that no. of moles of CaCO3 which will decompose is equivalent to the no. of CaO . Now it's just the matter of finding the no. of moles of CaCO3 .
<span>no.of moles=<span><span>mass /</span><span>relative molecular mass</span></span></span>
Answer:
https://newshamchem.weebly.com/uploads/2/2/0/3/22035226/molarity_&_worksheet_answer.pdf
question 9.
Explanation:
