A group of students where asked about the number of e-mails they each send that day. The results are: 0, 1, 1, 2, 3, 3, 4, 4, 6,
7, 8, 10, 11, 14, and 15. Which histogram correctly shows the data set?
1 answer:
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Note: a radioactive decay constant is always negative.
time = [natural log(ending amount / beginning amount)] / k
time = ln (20 / 24) / -.00011
time = ln (5/6) / -.00011
time = -.018232155683 / -.00011
time = <span> <span> <span> 165.7468698455 </span> </span> </span>
time = <span> <span> <span> 165.75 years
</span></span></span>
time = [natural log(ending amount / beginning amount)] / k
time = ln (20 / 24) / -.00011
time = ln (5/6) / -.00011
time = -.018232155683 / -.00011
time = <span> <span> <span> 165.7468698455 </span> </span> </span>
time = <span> <span> <span> 165.75 years
</span></span></span>