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SashulF [63]
3 years ago
14

Why does the definition of fair use remain ambiguous?

Computers and Technology
1 answer:
bogdanovich [222]3 years ago
8 0
Millions of dollars in legal fees have been spent attempting to define what qualifies as a fair use.

There are no hard-and-fast rules, only general guidelines and varied court decisions, because the judges and lawmakers who created the fair use exception did not want to limit its definition.

Like free speech, they wanted it to have an expansive meaning that could be open to interpretation.
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Write a program that prompts the user to enter two characters and display the corresponding major and year status. The first cha
nydimaria [60]

Answer:

  1. import java.util.Scanner;  
  2. public class Main {
  3.    public static void main(String[] args) {
  4.        Scanner input = new Scanner(System.in);
  5.        System.out.print("Please enter two characters: ");
  6.        String inputStr = input.nextLine();
  7.        if(inputStr.charAt(0) == 'B' || inputStr.charAt(0) == 'b'){
  8.            System.out.println("Biology");
  9.        }
  10.        else if(inputStr.charAt(0) == 'C' || inputStr.charAt(0)== 'c'){
  11.            System.out.println("Computer Science");
  12.        }
  13.        else if(inputStr.charAt(0) == 'I' || inputStr.charAt(0) == 'i')
  14.        {
  15.            System.out.println("Information Technology and Systems");
  16.        }
  17.        else{
  18.            System.out.println("Invalid major");
  19.        }
  20.        int num = Character.getNumericValue(inputStr.charAt(1));
  21.        if(num >= 1 && num <= 4){
  22.            switch (num){
  23.                case 1:
  24.                    System.out.println("freshman");
  25.                    break;
  26.                case 2:
  27.                    System.out.println("sophomore");
  28.                    break;
  29.                case 3:
  30.                    System.out.println("junior");
  31.                    break;
  32.                case 4:
  33.                    System.out.println("senior");
  34.                    break;
  35.            }
  36.        }
  37.        else{
  38.            System.out.println("Invalid year status");
  39.        }
  40.    }
  41. }

Explanation:

The code consists of two main parts. The part 1 is to validate the input major and print out the major according to the input character (Line 10 -22). If the input character is not matched with the target letters, a message invalid major will be displayed.

The part 2 is to validate the year status to make sure it only fall within the range of 1-4  (Line 26 -45). If within the range, the program will display the year major accordingly. If not a message invalid year status will be displayed.

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in your notes books and in your vopy

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