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Blababa [14]
3 years ago
5

Maribel thinks the tens digit goes up by 1 in these numbers. Do you agree?

Mathematics
1 answer:
podryga [215]3 years ago
7 0
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Does anyone know this? its for a test , please ?!
konstantin123 [22]

Answer:

11) Irrational number

12) Integer

13) Communitive property of addition

14) Distributive property of addition and multipacation

15) 26

16) 8

17) -41

18) 65

19) -5x-20

Step-by-step explanation:

Hope I helped

4 0
3 years ago
Which is true about the functional relationship shown in the graph?
Snowcat [4.5K]
We need a picture of the graph
8 0
3 years ago
Please help!<br><br><br> Solve the inequality for x<br><br> 3(x + 4) &gt; 4 - X
Maurinko [17]

Answer:

x>-2

Step-by-step explanation:

3(x + 4) > 4 - X

Distribute

3x+12> 4-x

Add x to each side

3x+12+x > 4-x+x

4x+12 > 4

Subtract 12 from each side

4x+12-12>4-12

4x> -8

Divide each side by 4

4x/4 > -8/4

x>-2

6 0
3 years ago
Read 2 more answers
Solve –3x^2 – 4x – 4 = 0
raketka [301]
-3x^2-6x+2x-4 =-3x (x-2)+2 (x-2) =(-3x+2)(x-2) -3x+2=0 X=2/3 X-2=0 X=2 Hope it helps! !!!!
4 0
3 years ago
Read 2 more answers
Which of the following statements are true of the graph of the function f(x)=(x+5)(x-3)?
mr_godi [17]

Answers: b, d and e

b.The graph has a relative minimum

d. The graph has an x intercept at 3,0

e. the graph has an y intercept at 0,-15

f(x)=(x+5)(x-3)

The given equation is in the form of f(x) = a(x-b)(x-c)

If 'a' is positive then graph has a relative minimum

If 'a' is negative then graph has a relative maximum

Here a=1 that is positive so graph has a relative minimum .

To find x intercept we set f(x) =0 and solve for x

0=(x+5)(x-3)

x+5 =0 -> x = -5 so x intercept is (-5,0)

x - 3=0 -> x= 3 so x intercept is (3,0)

To find y intercept we plug in 0 for x

y=(x+5)(x-3)

y=(0+5)(0-3) = -15

so y intercept is (0,-15)



5 0
3 years ago
Read 2 more answers
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