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Mrrafil [7]
3 years ago
5

Two step equations 3 ×-5=%13

Mathematics
1 answer:
kap26 [50]3 years ago
3 0
3x-5=13

Move -5 to the right side and change the sign

3x=13+5

Add 13+5

3x=18

Divide both sides by 3

X=6
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Divide. Give the quotient and remainder. 426÷8
Anna007 [38]
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8 0
3 years ago
2(5m^4n^-1)^3 simplify show work please
dangina [55]

Answer:

\large\boxed{2(5m^4n^{-1})^3=250m^{12}n^{-3}=\dfrac{250m^{12}}{n^3}}

Step-by-step explanation:

\text{Use}\\\\(ab)^n=a^nb^n\\\\(a^n)^m=a^{nm}\\\\a^{-n}=\dfrac{1}{a^n}\\-------------------\\\\2(5m^4n^{-1})^3=2(5)^3(m^4)^3(n^{-1})^3=2(125)m^{3\cdot4}n^{-1\cdot3}=250m^{12}n^{-3}=\dfrac{250m^{12}}{n^3}

8 0
3 years ago
PLEASE HELP The points (6, 8) and (x, 12) are two points on a graph of an inverse variation. Find the missing value. Show all wo
UNO [17]

Answer:

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Step-by-step explanation:

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6 0
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For problems 29 - 31 the graph of a quadratic function y=ax^2 + bx + c is shown. Tell whether the discriminant of ax^2 + bx + c
Elan Coil [88]

Answer:

29) discriminant  is positive

30) discriminant  is 0

31) discriminant  is negative

Step-by-step explanation:

the graph of a quadratic function y=ax^2 + bx + c is shown. Tell whether the discriminant of ax^2 + bx + c = 0 is positive, negative, or zero.

In the graph of question number 29 we can see that the graph intersects the x axis at two points

so the equation has 2 solutions.

When the equation has two solution then the discriminant is positive

In the graph of question number 30 we can see that the graph intersects the x axis at only one point

so the equation has only  1 solution.

When the equation has only one solution then the discriminant is equal to 0

In the graph of question number 30 we can see that the graph does not intersects the x axis  

so the equation has 2 imaginary solutions.

When the equation has two imaginary solutions then the discriminant is negative

3 0
3 years ago
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Natali5045456 [20]
1/3(12x - 6)

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4 0
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