When moving into the port, the cargo boat displaced 2200 ft³ of water. Since the density of water is 62.42 lb/ft³ and mass = density × volume, then the mass of the cargo boat on entering the port is

2200 × 62.42 = 137324 lbs

On leaving the port, it displaces 4000 ft³ of water. The mass of the cargo boat on leaving the port is

4000 × 62.42 = 249680 lbs

The difference in both masses is

249680 - 137324 = 112356 lbs

Therefore, they loaded 112356 lbs of cargo

4 0

3 years ago

Question below. Please answer it, its math.

AleksAgata [21]

Answer:

- 0.8

Step-by-step explanation:

The first thing we want to do here is simplify the expression -

$\frac{3}{5}$ ( 2x + 5 ) - 2x, Distribute the " $\frac{3}{5}$ " to elements within the parenthesis

= $\frac{3}{5}$ $*$ 2x + $\frac{3}{5}$ $*$ 5 - 2x, Focus on simplifying the expression " $\frac{3}{5}$ $*$ 2x + $\frac{3}{5}$ $*$ 5 "

= $2\cdot \frac{3}{5}x+5\cdot \frac{3}{5}$ - 2x

= $\frac{6x}{5}+3$ - 2x, Combine fractions

= $-\frac{4x}{5}$ + 3

= $-\frac{4}{5}$ x + 3

So we have our simplified expression " $-\frac{4}{5}$ x + 3, " with $-\frac{4}{5}$ being the coefficient of x. Our requirements are that this fraction should be expressed as a decimal, so we can simply divide the numerator by the denominator to figure that out,

- 4 / 5 = - 0.8,

Solution = - 0.8

4 0

3 years ago

Please help with this question and show work

alukav5142 [94]

The diagonals of a parallelogram bisect each other so
4x - 7 = x + 2 and
5y - 8 = 3y

4x - 7 = x + 2 so 3x = 9 and x = 3

5y - 8 = 3y so 2y = 8 and y = 4

4 0

3 years ago