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OLEGan [10]
3 years ago
11

The base of a cube has an area of

Mathematics
1 answer:
ch4aika [34]3 years ago
4 0

Answer:

Step-by-step explanation:

i) the side of the cube is V180=V36*5=6V5

ii) the total surface is 6*180=1080 cm^2

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6 pounds of potatoes cost $11.34. What is the unit price?
AveGali [126]
Your answer would be $1.89

You take 11.34 and divide it by 6. After that you’ll be 1.89 as your unit price.

1.89 is how much for 1 pound
8 0
3 years ago
Solve 6(x+1)3−10=740
Vera_Pavlovna [14]

Answer:

x=122/3

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

6(x+1)(3)−10=740

18x+18+−10=740(Distribute)

(18x)+(18+−10)=740(Combine Like Terms)

18x+8=740

18x+8=740

Step 2: Subtract 8 from both sides.

18x+8−8=740−8

18x=732

Step 3: Divide both sides by 18.

18x

18

=

732

18

x=

122

3

Answer:

x= 122/3

3 0
3 years ago
A researcher reports survey results by stating that the standard error of the mean is 25 the population standard deviation is 40
bezimeni [28]

Answer:

a) A sample of 256 was used in this survey.

b) 45.14% probability that the point estimate was within ±15 of the population mean

Step-by-step explanation:

This question is solved using the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

a. How large was the sample used in this survey?

We have that s = 25, \sigma = 400. We want to find n, so:

s = \frac{\sigma}{\sqrt{n}}

25 = \frac{400}{\sqrt{n}}

25\sqrt{n} = 400

\sqrt{n} = \frac{400}{25}

\sqrt{n} = 16

(\sqrt{n})^2 = 16^2[tex][tex]n = 256

A sample of 256 was used in this survey.

b. What is the probability that the point estimate was within ±15 of the population mean?

15 is the bounds with want, 25 is the standard error. So

Z = 15/25 = 0.6 has a pvalue of 0.7257

Z = -15/25 = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

45.14% probability that the point estimate was within ±15 of the population mean

3 0
3 years ago
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