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Answer:
25.8
Explanation:
Let's write the reaction between magnesium-phosphide and potassium:
Mg3P2 + K = Mg + K3P
And now let's balance this equation:
Mg3P2+6K=3Mg+2K3P
We see that the ratio of magnesium-phosphide and potassium is 1:6, which means that for every mole of magnesium-phosphide there need to be 6 moles of potassium.
Since we have 4.3 moles of Mg3P2, there need to be 6 • 4.3 = 25.8 moles of potassium.
Answer:
1.3 moles/ 1.33150727 moles
Explanation:
350g x 1 mol/262.86g = 1.3 moles
Ka is the acid dissociation equilibrium constant. The larger the value of the Ka, the stronger is the acid. To find Ka from pKa, the equation is:
pKa = -log[Ka]
@pKa = 7
7 = -log[Ka]
Ka = 1×10⁻⁷
@pKa = 10
10 = -log[Ka]
Ka = 1×10⁻¹⁰
This, pKa 7 is more acidic than pKa 10. The scale factor would be:
1×10⁻⁷/1×10⁻¹⁰ = 1,000
<em>Therefore, Compound A is 1,000 times more acidic than Compound B.</em>
