Answer: chemical property.
Explanation:
The chemical properties are the capacity or incapacity of a substance to transform into one or more different substance either by reacting with one or more different substances or by decomposition.
Such properties can only be observed when such change (reaction) takes place and the substance, therefore, is transformed into one or more different substances.
On the other hand, the physicial properties can be observed or measured without changing the composition of the sample.
I believe such reactions are called decomposition reactions. Decomposition reactions are reactions that involve breaking down a compound into smaller compounds or individual elements. They involve input of energy in the form of heat, electricity or light to break down the compounds. When light is used the reaction is referred to as photo decomposition while when heat is used the reaction is thermal decomposition reaction e.t.c. The general form of the reaction is AB = A + B.
The dichloromethane (DCM) has less density than water and also the polarity of water is much more than DCM. So the mixture of water and dichloromethane will always be a heterogeneous mixture. In the mixture dichloromethane will be always up of the water layer. The volume of the separatory funnel which contains the mixture of DCM and water must have to be more than the total volume of the liquids thus the volume of the funnel will be more than (50+50) = 100mL.
The caution have to consider during the separation are-
1. The separatory funnel have to shake well with lid and have to settle down for some times until the two liquid separated.
2. The lid should be open very slowly as the vapor pressure of DCM is more and it will float on the water.
3. After this the stopcock should be opened and slowly the water will come out first followed by DCM.
Answer: The volume of ethanolamine the student should pour out is 
Explanation:
To calculate the volume of ethanolamine we use the equation:
Density of ethanolamine = 
Mass of ethanolamine = 10.0 g
Volume of ethanolamine = ?
Putting values in above equation, we get:
Thus the volume of ethanolamine the student should pour out is
