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klemol [59]
2 years ago
12

WRITE THE ELECTRONIC CONFIGURATION OF THE FOLLOWING ELEMENT

Chemistry
1 answer:
Sloan [31]2 years ago
7 0

Answer:WHAT IS THE ELEMENT NAME?

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Create a comic strip that follows the journey of energy from the sun as it travels through the humpback whale
Arisa [49]

The path of energy flow from the sun to the humpback whale is as follows:

  • Sun---> Plankton ---> Small fishes ---> Humpback whale.

<h3>What is energy?</h3>

Energy is the ability to do work.

The primary source of energy on the earth is the sun.

The energy from the sun is used by producers to produce food on which other organisms depend on.

The energy from the sun gets to the humpback whale through producers such as plankton.

The path of energy flow from the sun to the humpback whale is as follows:

  • Sun---> Plankton ---> Small fishes ---> Humpback whale.

Learn more about energy flow at: brainly.com/question/21786633

4 0
2 years ago
Part a use these data to calculate the heat of hydrogenation of buta-1,3-diene to butane. c4h6(g)+2h2(g)→c4h10(g)
Reptile [31]

<u>Answer:</u> The heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H

The equation used to calculate enthalpy change is of a reaction is:

\Delta H_{rxn}=\sum [n\times \Delta H_{(product)}]-\sum [n\times \Delta H_{(reactant)}]

For the given chemical reaction:

C_4H_6(g)+2H_2(g)\rightarrow C_4H_{10}(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(1\times \Delta H_{(C_4H_{10})})]-[(1\times \Delta H_{(C_4H_6)})+(2\times \Delta H_{(H_2)})]

We are given:

\Delta H_{(C_4H_{10})}=-2877.6kJ/mol\\\Delta H_{(C_4H_6)}=-2540.2kJ/mol\\\Delta H_{(H_2)}=-285.8kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(1\times (-2877.6))]-[(1\times (-2540.2))+(2\times (-285.8))]\\\\\Delta H_{rxn}=234.2J

Hence, the heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

4 0
3 years ago
A sample of hydrated copper (II) sulfate (CuSO4•nH2O) is heated to 150°C and produces 103.74 g anhydrous copper (II) sulfate and
wariber [46]

Answer:

5

Explanation:

Firstly, we convert what we have to percentage compositions.

There are two parts in the molecule, the sulphate part and the water part.

The percentage compositions is as follows:

Sulphate- (103.74)/(103.74 + 58.55) × 100% = apprx 64%

The water part = 100 - 64 = 36%

Now, we divide the percentages by the molar masses.

For the CuSO4 molar mass is 64 + 32 + 4(16) = 160g/mol

For the H2O = 2(1) + 16 = 18g/mol

Now we divide the percentages by these masses

Sulphate = 64/160 = 0.4

Water = 36/18 = 2

The ratio is thus 0.4:2 = 1:5

Hence, there are 5 water molecules.

3 0
3 years ago
What’s the temperature at the boiling and freezing point of water in fanrenheit
Dominik [7]

Answer:

Boiling is 212* Freezing is 32*

Explanation:

It simple facts

5 0
2 years ago
What is thermal energy?
True [87]

good sir it seems your answer appears to be B

8 0
2 years ago
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