WRITE THE ELECTRONIC CONFIGURATION OF THE FOLLOWING ELEMENT
1 answer:
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Answer:
0.004548 M is the concentration of B at equilibrium at 500 K.
Explanation:
A(aq) ⇆ 2 B(aq)
Initially 3.00 M
At equilibrium 3.00 -x 2x
Equilibrium constant of the reaction at 500 K =
Concentration of A at 500 K at equilibrium , [A] = (3.00 -x )M
Concentration of B at 500 K at equilibrium,[B]= 2x
An expression of equilibrium constant is given as:
On solving for x:
x = 0.002274 M
[B] = 2 x = 2 × 0.002274 M = 0.004548 M
[A] = (3-x) = 3 M - 0.002274 M =2.997726 M
0.004548 M is the concentration of B at equilibrium.
Answer:
F = 0.0725 N
Explanation:
Given that,
The mass of peach, m = 7.4 g
We need to find the force acts on the peach when it falls from a tree. The force is given by :
F = mg
So,
So, the force is 0.0725 N.