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Nat2105 [25]
2 years ago
8

The bond energy between carbon and oxygen is 358 for a single bond (C–O) and 745 for a double bond (C=O). Why is the bond energy

higher for double-bonded carbon and oxygen (C=O)?
A. Additional bonds require less energy to break, so the bond energy is higher.

B. Additional electrons attract each other, decreasing the distance between atoms, and increasing bond energy.

C. Additional electrons repel each other, increasing the distance between atoms, and increasing bond energy.

D. Additional bonds require more energy to break, so the bond energy is higher.
Chemistry
1 answer:
erastovalidia [21]2 years ago
8 0

This problem is providing the bond energy for the bonds C-O and C=O which are 358 and 745 respectively, so that a feasible explanation to this behavior is required. At the end, one concludes the correct answer is C. "additional electrons repel each other, increasing the distance between atoms, and increasing bond energy" according to the following:

<h3>Bond energy:</h3><h3 />

In chemistry, we study the bond energy as the energy required to break the bond, binding two elements. In such a way, we can evidence that the more bonds between the atoms, the higher the bond energy such as in the case of C-O and C=O.

In such a way, since bonds are formed between valence electrons, we see that the more of these an atom has available for bonding, the farther away they will be, as they are repelled; thus, causing more distance between atoms and making the bond to be longer.

Hence, the greater the distance between two atoms in a bond, the higher the bond energy; that's why the answer to this question is C. Additional electrons repel each other, increasing the distance between atoms, and increasing bond energy.

Learn more about bond lengths: brainly.com/question/13683866

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Answer:

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Explanation:

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3 0
3 years ago
Will mark the brainiest later for correct answers! Please show work.
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Answer:

According to avogadro's law, 1 mole of every substance contains avogadro's number 6.023\times 10^{23} of particles and weighs equal to its molecular mass.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadros number}}

a. moles in 14.08 g of C_{12}H_{22}O_{11} = \frac{14.08g}{342.3g/mol}=0.04113moles

molecules in 14.08 g of C_{12}H_{22}O_{11} = 0.04113\times 6.023\times 10^{23}=0.2477\times 10^{23}

b. moles in 17.75 g of NaCl = \frac{17.75g}{58.5g/mol}=0.3034moles

molecules in 17.75 g of NaCl = 0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}

formula units 17.75 g of NaCl = 0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}

c. moles in 20.06 g of  CuSO_4.5H_2O= \frac{20.06g}{249.68g/mol}=0.08034moles

formula units in 20.06 g of  CuSO_4.5H_2O= 0.08034\times 6.023\times 10^{23}=0.4839\times 10^{23}

7 0
3 years ago
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vlada-n [284]
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8. Calculate the number of moles of eachsubstance.a. 5.45 x 1026 particles of methane, CH4
Klio2033 [76]

<em>ANSWER</em>

The number of moles of methane is 905.32 moles

STEP-BY-STEP EXPLANATION:

Given information

The number of particles of methane = 5.45 x 10^26 particles

Let x represents the number of moles of methane

To calculate the number of moles, we will be using the below formula

\text{Number of particles = number of moles x Avogadro's constant}

Recall that, the Avogadro's constant is given as

6.02\cdot10^{23}\begin{gathered} 5.45\cdot10^{26}\text{ = x }\cdot\text{ 6.02 }\cdot10^{23} \\ \text{Divide both sides by 6.02 }\cdot10^{23} \\ x\text{ = }\frac{5.45\cdot10^{26}}{6.02\cdot10^{23}} \\ x\text{ = }\frac{5.45}{6.02}\cdot10^{26\text{ - 23}} \\ x\text{ = 0.9053 }\cdot10^3 \\ x\text{ = 905.32 moles} \end{gathered}

Therefore, the number of moles of methane is 905.32 moles

6 0
2 years ago
The bond between iodine and fluorine in l-F would be a:
koban [17]

Answer:

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4 0
3 years ago
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