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riadik2000 [5.3K]
1 year ago
8

PLEASeee helppp in class rn. Pleaseee with 2,3, and 4.

Chemistry
1 answer:
asambeis [7]1 year ago
3 0

There are 115 protons in the element 115 and due to the large number of protons, the element does not exist in nature.

Also, the element can not be isolated in nature that is IUPAC had to require an independent confirmation of the element.

<h3>What is element 115?</h3>

We know that the periodic table is an arrangement of the atoms in order of increasing atomic number. We know that the larger the atomic number of the element, the less likely that the element would be stable in nature. The element that have been named 115 is called Moscovium and was discovered in Moscow as a product of a radioactive experiment. The number of protons in element 115 is 115 protons

Generally, the element number 115 does not exist in nature because if the proton number in an element exceeds 82, the repulsion between the protons would make it almost impossible for the nucleus to be a stable nucleus.

The reason why IUPAC had to request an independent confirmation of the element is because it does not exist in nature.

Learn more about element 115:brainly.com/question/27914234

#SPJ1

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How many moles in 4.93 x 10E23 atoms of silver?
leva [86]
<h3>Answer:</h3>

0.819 mol Ag

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

4.93 × 10²³ atoms Ag

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 4.93 \cdot 10^{23} \ atoms \ Ag(\frac{1 \ mol \ Ag}{6.022 \cdot 10^{23} \ atoms \ Ag})
  2. Divide:                              \displaystyle 0.818665 \ mol \ Ag

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.818665 mol Ag ≈ 0.819 mol Ag

8 0
3 years ago
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