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riadik2000 [5.3K]
11 months ago
8

PLEASeee helppp in class rn. Pleaseee with 2,3, and 4.

Chemistry
1 answer:
asambeis [7]11 months ago
3 0

There are 115 protons in the element 115 and due to the large number of protons, the element does not exist in nature.

Also, the element can not be isolated in nature that is IUPAC had to require an independent confirmation of the element.

<h3>What is element 115?</h3>

We know that the periodic table is an arrangement of the atoms in order of increasing atomic number. We know that the larger the atomic number of the element, the less likely that the element would be stable in nature. The element that have been named 115 is called Moscovium and was discovered in Moscow as a product of a radioactive experiment. The number of protons in element 115 is 115 protons

Generally, the element number 115 does not exist in nature because if the proton number in an element exceeds 82, the repulsion between the protons would make it almost impossible for the nucleus to be a stable nucleus.

The reason why IUPAC had to request an independent confirmation of the element is because it does not exist in nature.

Learn more about element 115:brainly.com/question/27914234

#SPJ1

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Answer:

11.35 g/cm³

Explanation:

If your rounding then 11.4. hope this helps :)

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How many particles would be found in a 1.224 g sample of K2O
lbvjy [14]

Answer:

9.96*10^21

Explanation:

Molar mass of K2O=29*2+16

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number of moles in the sample= 1.224/ 74

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4 0
3 years ago
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Which of these half-reactions represents reduction?
gogolik [260]

Answer: The half-reactions represents reduction are as follows.

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Explanation:

A half-reaction where addition of electrons take place or a reaction where decrease in oxidation state of an element  takes place is called reduction-half reaction.

For example, the oxidation state of Cr in Cr_{2}O^{2-}_{7} is +6 which is getting converted into +3, that is, decrease in oxidation state is taking place as follows.

Cr_{2}O^{2-}_{7} + 3 e^{-} \rightarrow Cr^{3+}

Similarly, oxidation state of Mn in MnO^{-}_{4} is +7 which is getting converted into +2, that is, decrease in oxidation state is taking place as follows.

MnO^{2-}_{4} + 5 e^{-} \rightarrow Mn^{2+}

Thus, we can conclude that half-reactions represents reduction are as follows.

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3 0
2 years ago
How many grams of lithium hypochlorite (LiClO) are there in 0.594 moles?
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Expression used :

\text{ Mass of }LiClO=\text{ Moles of }LiClO\times \text{ Molar mass of }LiClO

Now put all the given values in this expression, we get:

\text{ Mass of }LiClO=(0.594moles)\times (58.4g/mole)

\text{ Mass of }LiClO=34.7g

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3 years ago
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