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juin [17]
3 years ago
14

A steel cable lying flat on the floor drags a 20 kg block across a horizontal, frictionless floor. A 110 N force applied to the

cable causes the block to reach a speed of 4.2 m/s in a distance of 2.0 m
What is the mass of the cable?
Express your answer to two significant figures and include the appropriate units.
Physics
1 answer:
sammy [17]3 years ago
5 0

Answer:

The mass of the cable is 4.94 kg                                                                                                                                                                            

Explanation:

It is given that,

Mass of the block, m = 20 kg

Force applied to the cable, F = 110 N

Speed of the block, v = 4.2 m/s

Distance, d = 2 m

Let a is the acceleration of the block. It can be calculated using the third equation of motion as :

v^2-u^2=2ad

(4.2)^2-(0)^2=2a\times 2

a=4.41\ m/s^2

Let m' is the mass of the cable. It can be calculated using the second law of motion as :

m'=\dfrac{F}{a}-m

m=\dfrac{110\ N}{4.41\ m/s^2}-20

m = 4.94 kg

So, the mass of the cable is 4.94 kg. Hence, this is the required solution.

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For this wave, we see that point B and C have same displacement, but they are not in phase since in B the oscillation is going down while in C is going up.

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