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MatroZZZ [7]
2 years ago
5

the form of energy that is stored in large objects because of its internal condition, such as compression or tension, is called

____________ energy

Physics
1 answer:
shepuryov [24]2 years ago
8 0
Elastic potential energy is a form of energy that is stored in large objects because of its internal condition, such as compression or tension, is called elastic potential energy is the correct answer. 

The picture show of elastic potential energy!

Hope it helped you!

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Someone please help? :)
Gnoma [55]

Answer:

(A) F_N - mg\cos\theta

Explanation:

The net force perpendicular to the surface of the incline is the sum of the gravity force component, which is mgcos(theta), and the reactionary normal force caused by the surface of the incline. The sum is F_N - mgcos(theta) and is usually 0 which is why the object is not moving perpendicularly to the surface of the incline.

8 0
3 years ago
A cannon sits on the edge of a castle wall that is 15 m above the ground. A cannon ball leaves the cannon with an initial veloci
Juli2301 [7.4K]

Answer:

a

Explanation:

4 0
2 years ago
The lens in the eyepiece of a telescope magnifies light by bending it. What is this bending called?
tresset_1 [31]
I believe that it is called refracting...
7 0
3 years ago
Read 2 more answers
Kara drops a rock from the edge of a cliff and it takes 7.00 s for the rock to reach the ground. What is the cliff’s height?
stepan [7]

Answer:

h = 204.1 m

Explanation:

Given that,

Time taken to reach the ground, t = 7 s

We need to find the height of the cliff. We can find it using second equation of kinematics as follows :

h=ut+\dfrac{1}{2}at^2

Here,

u = 0 (at rest initially)

a = g

So,

h=\dfrac{1}{2}gt^2\\\\h=\dfrac{1}{2}\times 9.8\times 7^2\\\\h=204.1\ m

So, the cliff's height is 204.1 m.

5 0
2 years ago
Work done of frictional force from instant ​
Liono4ka [1.6K]

Answer:

  • -100\ J

Step-by-step explanation:

<u>1. Find acceleration:</u>

  • m=2\ kg
  • F=-5\ N
  • a=\frac{F}{m}  (Newton's second law)
  • a=\frac{-5}{2} =-2.5\ \frac{m}{s^{2}}

<u>2. Find distance traveled:</u>

  • v_0=10\ \frac{m}{s}
  • v=0
  • a=-2.5\ \frac{m}{s^{2} }
  • v^2-v_0^2=2ad (Kinematic equation)
  • -100=-5d
  • d=20\ m

3. Find work done by friction:

  • W=Fd (Work formula when angle between Force and Displacement vectors are 0°)
  • W=-5\times20=-100\ J
4 0
3 years ago
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