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MatroZZZ [7]
2 years ago
5

the form of energy that is stored in large objects because of its internal condition, such as compression or tension, is called

____________ energy

Physics
1 answer:
shepuryov [24]2 years ago
8 0
Elastic potential energy is a form of energy that is stored in large objects because of its internal condition, such as compression or tension, is called elastic potential energy is the correct answer. 

The picture show of elastic potential energy!

Hope it helped you!

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what is the resistance of a car light bulb that conducts 0.025A current when connected to a 12V car accumulator? is the current
Sophie [7]

One form of Ohm's Law says . . . . . Resistance = Voltage / Current .

R = V / I

R = (12 v) / (0.025 A)

R = (12 / 0.025) (V/I)

<em>R = 480 Ohms</em>

I don't know if the current in the bulb is steady, because I don't know what a car's "accumulator" is.  (Floogle isn't sure either.)

If you're referring to the car's battery, then the current is quite steady, because the battery is a purely DC storage container.

If you're referring to the car's "alternator" ... the thing that generates electrical energy in a car to keep the battery charged ... then the current is pulsating DC, because that's the form of the alternator's output.  

7 0
3 years ago
An object has a forward force of 100N and a reverse force of 25N. What is the resultant force?
iragen [17]

<u>Given</u><u>:</u>

  • An object has a forward force = 100N

  • An object has a reverse force = 25N

<u>To</u><u> </u><u>find</u><u> </u><u>out</u><u>:</u>

What is the resultant force?

<u>Solution</u><u>:</u>

Resultant Force = Forward force + Reserve force

= 100 N + ( - 25 N )

= 75 N

4 0
2 years ago
Read 2 more answers
Our eyes are typically 6 cm apart. Suppose you are somewhat unique, and yours are 9.50 cm apart. You see an object jump from sid
Serhud [2]

Answer: 12.67 cm, 8 cm

Explanation:

Given

Normal distance of separation of eyes, d(n) = 6 cm

Distance of separation is your eyes, d(y) = 9.5 cm

Angle created during the jump, θ = 0.75°

To solve this, we use the formula,

θ = d/r, where

θ = angle created during the jump

d = separation between the eyes

r = distance from the object

θ = d/r

0.75 = 9.5 / r

r = 9.5 / 0.75

r = 12.67 cm

θ = d/r

0.75 = 6 / r

r = 6 / 0.75

r = 8 cm

Thus, the object is 12.67 cm far away in your own "unique" eyes, and just 8 cm further away to the normal person eye

8 0
3 years ago
B. Jerome plays middle linebacker for South's varsity football team. In a game against
weqwewe [10]

Answer:

Option D

670 Kg.m/s

Explanation:

Initial momentum is given by mv=82*5.6=459.2 Kg.m/s (taking eastward as positive)

Final momentum is also mv but v being westward direction, we take it negative

Final momentum=82*-2.5= -205 Kg.m/s

Change in momentum=Final momentum-Initial momentum=-205-459.2=-664.2 Kg.m/s

Impulse=change in momentum=664.2 Kg.m/s rounded off as 670 Kg.m/s

4 0
3 years ago
Asap pls hurry will mark brainiest
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