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3 years ago

8

Now check your predictions. In GeoGebra, rotate quadrilateral ABCD about the origin through angles of 90°, 180°, 270°, and 360°.

Enter the coordinates of the vertices of quadrilateral A′B′C′D′ in the table. Paste a screen capture of the images you created below the table.

1 answer:

svet-max [94.6K]3 years ago

7 0

Answer:

Plato answer.

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Every time Luisa bakes a batch of brownies she uses 1/2 cup of chocolate if she has 3/2 cups of chocolate remaining how many bat

kakasveta [241]

Answer:

she can make 4 batches of brownies

Step-by-step explanation:

since she already made a batch of brownie with 1/2 cup and she has 3/2 cups left, that means she can make 3 more

3+1=4

hope this helps

3 0

3 years ago

What is the solution to this system of equations?

antoniya [11.8K]

Answer:

c

Step-by-step explanation:

Since both equations express y in terms of x we can equate the right sides

3x + 5 = - x + 3 ( add x to both sides )

4x + 5 = 3 ( subtract 5 from both sides )

4x = - 2 ( divide both sides by 4 )

x = - 0.5

substitute x = - 0.5 in either of the 2 equations

using y = - x + 3 then y = 0.5 + 3 = 3.5

solution is (- 0.5, 3.5 ) → c

6 0

4 years ago

A bag contains 5 red blocks, 7 yellow blocks, and 8 green blocks. What is the ratio of green blocks to total blocks? Choose all

zysi [14]

Answer:

E

Step-by-step explanation:

Total: 20 blocks

Green: 8

8/20

Please mark as Brainliest! :)

Have a nice day.

3 0

3 years ago

Read 2 more answers

Solve this x²+8/10 -x = 10/2

AysviL [449]

$x^2+\frac{8}{10}-x=\frac{10}{2}\\
x^2-x+\frac{8}{10}-\frac{10}{2}=0\\
x^2-x+\frac{8}{10}-\frac{50}{10}=0\\
x^2-x-\frac{42}{10}=0\\
x^2-x+\frac{1}{4}-\frac{1}{4}-\frac{42}{10}=0\\
(x-\frac{1}{2})^2=\frac{1}{4}+\frac{42}{10}\\
(x-\frac{1}{2})^2=\frac{5}{20}+\frac{84}{20}\\
(x-\frac{1}{2})^2=\frac{89}{20}\\
x-\frac{1}{2}=\sqrt{\frac{89}{20}} \vee x-\frac{1}{2}=-\sqrt{\frac{89}{20}}\\
x=\frac{1}{2}+\frac{\sqrt{89}}{\sqrt{20}} \vee x=\frac{1}{2}-\frac{\sqrt{89}}{\sqrt{20}}\\


$
$x=\frac{1}{2}+\frac{\sqrt{89}}{2\sqrt{5}} \vee x=\frac{1}{2}-\frac{\sqrt{89}}{2\sqrt5}}\\
x=\frac{1}{2}+\frac{\sqrt{445}}{10} \vee x=\frac{1}{2}-\frac{\sqrt{445}}{10}}\\
x=\frac{5+\sqrt{445}}{10} \vee x=\frac{5-\sqrt{445}}{10}}\\$

7 0

4 years ago

Given that the square root function is only defined for non-negative numbers, define the domain of f in terms of c. {x | ≥ 0}

diamong [38]

Answer:

c:(0;+∞)

Step-by-step explanation:

Given the situation, that the square root function only allows you values above than "0" (not equal neither), then you must consider that every value above 0 belongs to it's domain.

Then, to express the domain, going from your most negative number, to your most possitive number (in this case all positive number, thats why we use infinite) you must use the parenthesis wich means, you are not considering the value (in this case 0), but the value right after it, to the next value that as we said before, is inifinite. Also remember, that when you express a domain, and use infinite (despite it's going to negative way, or possitive way, it also goes with parenthesis).

5 0

3 years ago