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laila [671]
3 years ago
14

PLEASE HELP ME THIS IS DUE IN TWO HOURS! :(

Mathematics
1 answer:
ikadub [295]3 years ago
7 0

Answer:224 squared

Step-by-step explanation:

H

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Hlp me plz i will give you guys 25 points
mart [117]
(A4+a2) hoped this helps
6 0
3 years ago
Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive
NeX [460]

Answer:

(a) 0.343

(b) 0.657

(c) 0.189

(d) 0.216

(e) 0.353

Step-by-step explanation:

Let P(a vehicle passing the test) = p

                        p = \frac{70}{100} = 0.7  

Let P(a vehicle not passing the test) = q

                         q = 1 - p

                         q = 1 - 0.7 = 0.3

(a) P(all of the next three vehicles inspected pass) = P(ppp)

                           = 0.7 × 0.7 × 0.7

                           = 0.343

(b) P(at least one of the next three inspected fails) = P(qpp or qqp or pqp or pqq or ppq or qpq or qqq)

      = (0.3 × 0.7 × 0.7) + (0.3 × 0.3 × 0.7) + (0.7 × 0.3 × 0.7) + (0.7 × 0.3 × 0.3) + (0.7 × 0.7 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.3)

      = 0.147 + 0.063 + 0.147 + 0.063 + 0.147 + 0.063 + 0.027

      = 0.657

(c) P(exactly one of the next three inspected passes) = P(pqq or qpq or qqp)

                 =  (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

                 = 0.063 + 0.063 + 0.063

                 = 0.189

(d) P(at most one of the next three vehicles inspected passes) = P(pqq or qpq or qqp or qqq)

                 =  (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7) + (0.3 × 0.3 × 0.3)

                 = 0.063 + 0.063 + 0.063 + 0.027

                 = 0.216

(e) Given that at least one of the next 3 vehicles passes inspection, what is the probability that all 3 pass (a conditional probability)?

P(at least one of the next three vehicles inspected passes) = P(ppp or ppq or pqp or qpp or pqq or qpq or qqp)

=  (0.7 × 0.7 × 0.7) + (0.7 × 0.7 × 0.3) + (0.7 × 0.3 × 0.7) + (0.3 × 0.7 × 0.7) + (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

= 0.343 + 0.147 + 0.147 + 0.147 + 0.063 + 0.063 + 0.063

                  = 0.973  

With the condition that at least one of the next 3 vehicles passes inspection, the probability that all 3 pass is,

                         = \frac{P(all\ of\ the\ next\ three\ vehicles\ inspected\ pass)}{P(at\ least\ one\ of\ the\ next\ three\ vehicles\ inspected\ passes)}

                         = \frac{0.343}{0.973}

                         = 0.353

3 0
3 years ago
Read 2 more answers
The sum of two numbers is negative fifteen, and one number is five less than the other. Using the variables m and n to represent
Likurg_2 [28]

We need to use the variables m and n to represent both numbers.

Their sum must equal -15. Therefore, we can write the next equation:

m + n = -15

If one number is five less than the other, we need to choose one variable and then we can write it in terms of the other variable. Then:

n = m-5

To find the value for each number, we can replace the n equation on the first equation:

m + n = -15

m + (m-5)= -15

Then:

m + m - 5 = -15

2m -5 = -15

Solve the equation for m:

Add both sides 5 units:

2m - 5 +5 = -15+5

2m = -10

Divide both sides by 2:

2m/2 = -10/2

m = -5

Finally, replace the m value on the first equation:

m + n = -15

-5 + n = -15

Then, solve the equation for n:

Add both sides by 5:

-5+5 + n = -15 +5

n = -10

Hence, both numbers are m=-5 and n= -10.

The equations separated by a comma are m + n = -15,n = m-5.

The numbers separated by a comma are -5,-10.

6 0
1 year ago
Can anybody help me with this question?
Bogdan [553]
For number 16 we need to write the data as a ratio then convert to a unit rate (amount per 1)...

308/14 = x/1

Cross multiply

14x = 308
x = 308/14
x = 22

So the fuel efficiency is
22 miles per 1 gallon or

22/1

For number 17, since the car was driven at 48 mph, we just have to divide distance driven by speed to get how long it took...

288 miles ÷ 48 mph =

6 hours
6 0
3 years ago
Which explains how to find the quotient of the division below? Negative 3 and one-third divided by StartFraction 4 over 9 EndFra
Ulleksa [173]

Answer:

(B) Write Negative 3 and one-third as Negative StartFraction 10 over 3 EndFraction, and find the reciprocal of StartFraction 4 over 9 EndFraction as StartFraction 9 over 4 EndFraction. Then, rewrite Negative 3 and one-third divided by StartFraction 4 over 9 EndFraction as Negative StartFraction 10 over 3 EndFraction times StartFraction 9 over 4 EndFraction. The quotient is Negative 7 and StartFraction 6 over 12 EndFraction = Negative 7 and one-half.

Step-by-step explanation:

To find the quotient of the division:

-3\dfrac13 \div \dfrac49

Step 1: \text{Write}$ $ -3\dfrac13$ as $ -\dfrac{10}{3}

-3\dfrac13 \div \dfrac49 =  -\dfrac{10}{3} \div \dfrac49

Step 2: Find the reciprocal of  \dfrac94

-\dfrac{10}{3} \times \dfrac94\\=-7\dfrac12

4 0
3 years ago
Read 3 more answers
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