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Digiron [165]
3 years ago
9

Which explanation below best describes why meiosis produces haploid cells?

Biology
1 answer:
Agata [3.3K]3 years ago
7 0

Answer:

Egg and sperm cells have to have half the number of chromosomes as in  body cells so when they combine to form a zygote, the zygote is diploid  and has the correct number of chromosomes. This explanation describes why meiosis produces haploid cells.

Explanation:

Meiosis is a type of cell division in which four haploid cells are produced from a diploid parent cell having two copies of each chromosome, where the number of chromosomes in the parent cell is reduced to half by undergoing DNA replication and nuclear division. Diploid cell contains two copies of each chromosome, one inherited from mother and the other from father while haploid cell contains only one copy of each chromosome. Examples of diploid cells (somatic cells) are skin, blood, muscle cells etc. Eggs or ovum (female gametes) and sperm (male gametes) are haploid reproductive cells. If the total number of chromosomes in a diploid cell is represented as '2n', then the number of chromosomes in a haploid cell is 'n'.  During the fertilization process in an organism, the correct number of chromosomes is restored when the haploid male and female gamete combined to form a single diploid zygote, which is the first developmental stage of an organism.

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Explanation:

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Which of these methods is NOT solely applicable to biological classifications?
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g If a person takes a prescribed dose of 10 milligrams of Valium, the amount of Valium in that person's bloodstream at any time
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Answer:

a. 8.1 milligrams

b. 40.07 hours

c. 8.859 milligrams

Explanation:

If a person takes a prescribed dose of 10 milligrams of Valium, the amount of Valium in that person's bloodstream at any time can be modeled by

A_{t}=10e^{-0.0173t}

Where A(t) = amount of Valium remaining in the blood after t hours

t = time or duration after the drug is taken

a. we have to calculate the amount of drug remaining in the bloodstream after 12 hours

A_{12}=10e^{-0.0173\times12}

A_{12}=10e^{-0.2076}

                = 10×0.81253

                = 8.1 milligrams

b. In this part we have to calculate the time when A(t) = 5 milligrams

5=10e^{-0.0173\timest}

\frac{5}{10}=e^{-0.0173t}

0.5 = e^{-0.0173t}

Now we take natural log on both the sides of the equation.

ln(0.5) = ln(e^{-0.0173t})

-0.69314 = -0.0173t

t = \frac{0.69314}{0.0173}

t = 40.0658

 ≈ 40.07 hours

c. In this part we have to calculate the rate, by which amount of drug will decay in the bloodstream after 7 hours.

A_{7}=10e^{-0.0173\times7}

A_{7}=10e^{-0.1211}

              = 10×0.8859

              = 8.859 milligrams

6 0
3 years ago
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