Answer:
C.) v = 50 m/s
Explanation:
The relationship between position vs. time graph and velocity is that the derivative (slope) of the position vs. time graph gives you velocity. In other words, find the slope to get the velocity.
Select two arbitrary points. I'll choose (3s, 225m) and (0s, 75m).
Now use the slope equation:
v = 50 m/s
Hopes this helps!
Answer:
Acceleration of the ship,
Explanation:
It is given that,
Mass of both ships,
Distance between two ships, d = 110 m
The gravitational force between two ships is given by :
F = 8.38 N
Let a is the acceleration. Now, using second law of motion as :
So, the acceleration of either ship due to the gravitational attraction of the other is . Hence, this is the required solution.
Answer:
(a) t = 1.14 s
(b) h = 0.82 m
(c) vf = 7.17 m/s
Explanation:
(b)
Considering the upward motion, we apply the third equation of motion:
where,
g = - 9.8 m/s² (-ve sign for upward motion)
h = max height reached = ?
vf = final speed = 0 m/s
vi = initial speed = 4 m/s
Therefore,
<u>h = 0.82 m</u>
Now, for the time in air during upward motion we use first equation of motion:
(c)
Now we will consider the downward motion and use the third equation of motion:
where,
h = total height = 0.82 m + 1.8 m = 2.62 m
vi = initial speed = 0 m/s
g = 9.8 m/s²
vf = final speed = ?
Therefore,
<u>vf = 7.17 m/s</u>
Now, for the time in air during downward motion we use the first equation of motion:
(a)
Total Time of Flight = t = t₁ + t₂
t = 0.41 s + 0.73 s
<u>t = 1.14 s</u>