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4 years ago

Which data set has the smallest standard deviation?

2 answers:

8 0

The answer would be B.
<span>
Standard deviation basically measures how spread out the values are. Without solving, you can easily tell which one among your choices have a smaller deviation. The closer the values are to each other the smaller the standard deviation. The values of choice B are the closest together, so you can assume that they have the smallest standard deviation. </span>

lubasha [3.4K]4 years ago

7 0

Answer:

(B)1000, 1001, 1002, 1000, 1001, 1001

Explanation:

Standard deviation helps in measuring how spread out the values actually are. Without solving for the standard deviation, the smallest standard deviation of the given data sets can be easily guessed.

The closer the values are to each other, the smaller is the standard deviation. From the given data sets, The values of choice B that are 1000, 1001, 1002, 1000, 1001, 1001 are the closest together and in rest of the options the data sets hare not close to each other, so one can assume that they have the smallest standard deviation.

Hence, option B is correct.

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How many components do vectors have, and what are they?

zepelin [54]

Answer:

There are two components for a two-dimensional coordinate system/vector.

Explanation:

For two-dimensional vectors, such as velocity, acceleraton, etc, there are two components, the x- and y-components.

These components could be rotated or translated, depending on the coordinate system.

Instead of rectangular cartesian system, the components could also be in the form of polar coordinates, such as radius and theta (angle).

For three-dimensional vectors, such as velocity in space, there are three components, in various coordinate systems.

8 0

3 years ago

Where is the near point of an eye for which a contact lens with a power of +2.55 diopters is prescribed?Where is the far point o

tankabanditka [31]

Answer:

(a). The eye's near point is 68.98 cm from the eye.

(b). The eye's far point is 33.33 cm from the eye.

Explanation:

Given that,

Power = 2.55 D

Object distance = 25 cm for near point

Object distance = ∞ for far point

Suppose where is the far point of an eye for which a contact lens with a power of -3.00 D is prescribed for distant vision?

(a) We need to calculate the focal length

Using formula of power

$f =\dfrac{1}{P}$

Put the value into the formula

$f=\dfrac{100}{2.55}$

$f=39.21\ cm$

We need to calculate the image distance

Using formula of lens

$\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}$

Put the value into the formula

$\dfrac{1}{39.21}=\dfrac{1}{v}-\dfrac{1}{-25}$

$\dfrac{1}{39.21}-\dfrac{1}{25}=\dfrac{1}{v}$

$\dfrac{1}{v}=-\dfrac{1421}{98025}$

$v=-68.98\ cm$

The eye's near point is 68.98 cm from the eye.

(b). We need to calculate the focal length

Using formula of power

$f =\dfrac{1}{P}$

Put the value into the formula

$f=-\dfrac{100}{3.00}$

$f=-33.33\ cm$

We need to calculate the image distance

Using formula of lens

$\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}$

Put the value into the formula

$\dfrac{1}{-33.33}=\dfrac{1}{v}-\dfrac{1}{\infty}$

$-\dfrac{1}{33.33}+\dfrac{1}{\infty}=\dfrac{1}{v}$

$\dfrac{1}{v}=-\dfrac{1}{33.33}$

$v=-33.33\ cm$

The eye's far point is 33.33 cm from the eye.

Hence, (a). The eye's near point is 68.98 cm from the eye.

(b). The eye's far point is 33.33 cm from the eye.

5 0

3 years ago

What provides the force necessary to start a building or bridge oscillating?

Andrew [12]

Usually, the forces that start the oscillation of buildings are the wind and microearthquakes.

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3 years ago

Which group contains elements that have the following characteristics:

Harrizon [31]

actually the answer is B because Chlorine, sulfur, and silicon. Chlorine is a halogen and gas. Sulfur forms an ion with a -2 charge in ionic bonds. Silicon is a well-known metalloid.

6 0

3 years ago

A geologist is trying to determine what time period a layer of rock was formed.

vodka [1.7K]

Answer:

Explanation:

You always want to test as many samples as possible

8 0

3 years ago