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san4es73 [151]
3 years ago
13

Which data set has the smallest standard deviation?

Physics
2 answers:
777dan777 [17]3 years ago
8 0
The answer would be B.
<span>
Standard deviation basically measures how spread out the values are. Without solving, you can easily tell which one among your choices have a smaller deviation. The closer the values are to each other the smaller the standard deviation. The values of choice B are the closest together, so you can assume that they have the smallest standard deviation. </span>
lubasha [3.4K]3 years ago
7 0

Answer:

(B)1000, 1001, 1002, 1000, 1001, 1001

Explanation:

Standard deviation helps in  measuring how spread out the values actually are. Without solving for the standard deviation, the smallest standard deviation of the given data sets can be easily guessed.

The closer the values are to each other, the smaller is the standard deviation. From the given data sets, The values of choice B that are 1000, 1001, 1002, 1000, 1001, 1001 are the closest together and in rest of the options the data sets hare not close to each other, so one can assume that they have the smallest standard deviation.

Hence, option B is correct.

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A 70 kg hunter, standing on frictionless ice, shoots a 42 g bullet horizontally at a speed of 590 m/s . Part A Part complete Wha
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Answer:

The recoil velocity is 0.354 m/s.

Explanation:

Given that,

Mass of hunter = 70 kg

Mass of bullet = 42 g = 0.042 kg

Speed of bullet = 590 m/s

We need to calculate the recoil speed of hunter

Using conservation of momentum

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}

Where,m_{1} = mass of hunter

m_{2} = mass of bullet

u = initial velocity

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Put the value in the equation

0+0=70\times v_{1}+0.042\times590

v_{1}=-\dfrac{0.042\times590}{70}

v=-0.354\ m/s

Hence, The recoil velocity is 0.354 m/s.

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3 years ago
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Answer:

W = 1418.9 J = 1.418 KJ

Explanation:

In order to find the work done by the pull force applied by Karla, we need to can use the formula of work done. This formula tells us that work done on a body is the product of the distance covered by the object with the component of force applied in the direction of that displacement:

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where,

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d = distance covered = 10 m

θ = Angle with horizontal = 20°

Therefore,

W = (151 N)(10 m) Cos 20°

<u>W = 1418.9 J = 1.418 KJ</u>

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