Answer:
1.788 × 10⁷ g
Explanation:
Let's consider the following balanced equation.
2 H₂ + O₂ → 2 H₂O
We can establish the following relations.
- The molar mass of H₂ is 2.016 g/mol.
- The molar ratio of H₂ to H₂O is 2:2.
- The molar mass of H₂O is 18.02 g/mol.
The mass of H₂O obtained from 200.0 kg (200.0 × 10³ g = 2.000 × 10⁶ g) of H₂ is:
Answer: Catalyst B
Explanation:
Allows reactions to proceed at much lower energy levels than without.
2) 1
3) 1
4) 2
5) 3 or 2, I’m not sure
6) 1
7) 2
8) 1
9) 4
10) 2
11) 3
12) 1
I hope this helps, good luck.
Answer:
11.31g NaClO₂
Explanation:
<em> Is given 250mL of a 1.60M chlorous acid HClO2 solution. Ka is 1.110x10⁻². What mass of NaClO₂ should the student dissolve in the HClO2 solution to turn it into a buffer with pH =1.45? </em>
It is possible to answer this question using Henderson-Hasselbalch equation:
pH = pKa + log₁₀ [A⁻] / [HA]
<em>Where pKa is -log Ka = 1.9547; [A⁻] is the concentration of the conjugate base (NaClO₂), [HA] the concentration of the weak acid</em>
You can change the concentration of the substance if you write the moles of the substances:
[Moles HClO₂] = 250mL = 0.25L×(1.60mol /L) = <em>0.40 moles HClO₂</em>
Replacing in H-H expression, as the pH you want is 1.45:
1.45 = 1.9547 + log₁₀ [Moles NaClO₂] / [0.40 moles HClO₂]
-0.5047 = log₁₀ [Moles NaClO₂] / [0.40 moles HClO₂]
<em>0.3128 = </em>[Moles NaClO₂] / [0.40 moles HClO₂]
0.1251 = Moles NaClO₂
As molar mass of NaClO₂ is 90.44g/mol, mass of 0.1251 moles of NaClO₂ is:
0.1251 moles NaClO₂ ₓ (90.44g / mol) =
<h3>11.31g NaClO₂</h3>
