Answer: infinite answers, jk there is like a lot tho
Step-by-step explanation: The sum of x and y is 79. In other words, x plus y equals 79 and can be written as equation A:
x + y = 79
The difference between x and y is 23. In other words, x minus y equals 23 and can be written as equation B:
x - y = 23
Now solve equation B for x to get the revised equation B:
x - y = 23
x = 23 + y
Then substitute x in equation A from the revised equation B and then solve for y:
x + y = 79
23 + y + y = 79
23 + 2y = 79
2y = 56
y = 28
Now we know y is 28. Which means that we can substitute y for 28 in equation A and solve for x:
x + y = 79
x + 28 = 79
X = 51
Summary: The sum of the two numbers is 79 and their difference is 23. What are the two numbers? Answer: 51 and 28 as proven here:
Sum: 51 + 28 = 79
Difference: 51 - 28 = 23
Please give me brainliest
Answer:
2x3=6 and that the number of frogs heather has or you can do this Ava has 2 frogs and heather has 1/3 more then take the 2 and add it to the 1 and that makes three. then take both of the threes and add them together and you then have the same number of 6
Step-by-step explanation:
Answer:
After 16 months, Kenya will have paid $5,550
Step-by-step explanation:
This is a guess and check type of a problem. You guess a number of months, plug it into x, and see if both equations come out with the same answer.
If you plug 16 into the first dealer's equation, you get y= 200(16) + 2350. Solving this equation will mean y equals 5550.
If you plug 16 into the second dealer's equation, you get y= 175(16) + 2750.
Solving this equation will mean y also equals 5550.
2x - 6 = 18
2x = 18 + 6 (24)
2x = 24
x = 12
<span>3x + 9 = 2x + 24
3x + 9 = 2x + 24 - 9 (2x + 15)
3x = 2x + 15
3x - 2x = 15
x = 15
</span><span>4x = 2.4? 0.4x = 2.4? I can't tell what the question is. Let me know in the comments and I'll answer it.
</span>
<span>5x + 4 = 24
5x = 24 - 4 (20)
5x = 20
x = 4
</span><span>2x / 3 = 4
2x = 4 * 3 (12)
x = 6
</span><span>3(x + 7) = 51
3x + 21 = 51
3x = 51 - 21 (30)
3x = 30
x = 10
Hope I helped :)</span>
