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Serggg [28]
3 years ago
14

1. Solve -35 = -5x ........................

Mathematics
2 answers:
vovangra [49]3 years ago
7 0
-5x = -35
X= -35/-5 = 7
Valentin [98]3 years ago
3 0

Answer:

x = 7.

Step-by-step explanation:

-5x = -35

x = -35 / -5 = 7.

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Write the quadratic equation whose roots are −6 and 2 , and whose leading coefficient is 5 . (use the letter x to represent the
White raven [17]
<span>Here let the quadratic equation be ax^2 + bx + c We know that a=5 from the question. Since the roots are 6 and 2, the quadratic equation would take the form of a product like (a1x-b1)(a2x-b2). However, let's assume that a2=1 and b2=6, Since a=5, a1=5, then 5x-b1=5(x-2). Solving this shows that b1=10 So, the equation is (5x-10)(x-6)</span>
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3 years ago
According to the Rational Root Theorem, which number is a potential root of f(x) = 9x
MAVERICK [17]

Answer:

The answer is below....V

Step-by-step explanation:

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3 years ago
HELP ME PLEASE Find the slope of the line and write it as a rate of change.
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Answer:

1

Step-by-step explanation:

6 0
3 years ago
13. A catapult launches a boulder wint an upward velocity of 122 feet per second the height of the boulder (h) in feet after t s
SashulF [63]
For this case we have the following expression:
 h (t) = - 16t ^ 2 + 122t + 10
 We look for the maximum of the function, for this, we derive:
 h '(t) = - 32t + 122
 We match zero:
 -32t + 122 = 0
 We cleared t:
 t = 122/32
 t = 3.8125 s
 Then, the maximum height will be:
 h (3.8125) = - 16 * (3.2185) ^ 2 + 122 * (3.2185) +10
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 Answer:
 
It takes the boulder to reach maximum height about:
 
t = 3.8125 s
 
the boulders maximum height is:
 
236.92 feet
3 0
4 years ago
(Geometry course question) Explain why it is not possible to construct an equilateral triangle that has
Nutka1998 [239]

Answer:

  √3 is irrational

Step-by-step explanation:

The location of the third point of a triangle can be found using a rotation matrix to transform the coordinates of the given points.

<h3 /><h3>Location of point C</h3>

With reference to the attached figure, the slope of line AC is √3, an irrational number. This means the line AC <em>never passes through a point with integer coordinates</em>. (Any point with integer coordinates would be on a line with rational slope.)

<h3>Equilateral triangle</h3>

The line segments making up an equilateral triangle are separated by an angle of 60°. If two vertices are on grid squares, the third must be a rotation of one of them about the other through an angle of 60°. The rotation matrix is irrational, so the rotated point must have irrational coordinates.

The math of it is this. For rotation of (x, y) counterclockwise 60° about the origin, the transformation matrix is ...

  \left[\begin{array}{cc}\cos(60^\circ)&\sin(60^\circ)\\-\sin(60^\circ)&\cos(60^\circ)\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right]=\left[\begin{array}{c}x'\\y'\end{array}\right]

Cos(60°) is rational, but sin(60°) is not. For any non-zero rational values of x and y, the sum ...

  cos(60°)·x + sin(60°)·y

will be irrational.

As in the attached diagram, if one of the coordinates of the rotated point (B) is zero, then one of the coordinates of its image (C) will be rational. The other image point coordinate cannot be rational.

6 0
2 years ago
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