we know that center of mass is given as
r = (m₁ + m₂
)/(m₁ + m₂)
taking derivative both side relative to "t"
dr/dt = (m₁ d/dt + m₂ d
/dt)/(m₁ + m₂)
v = (m₁ + m₂
)/(m₁ + m₂)
taking derivative again relative to "t" both side
dv/dt = (m₁ d/dt + m₂ d
/dt)/(m₁ + m₂)
a= (m₁ + m₂
)/(m₁ + m₂)
Answer:
Final velocity of electron,
Explanation:
It is given that,
Electric field, E = 1.55 N/C
Initial velocity at point A,
We need to find the speed of the electron when it reaches point B which is a distance of 0.395 m east of point A. It can be calculated using third equation of motion as :
........(1)
a is the acceleration,
We know that electric force, F = qE
Use above equation in equation (1) as:
v = 647302.09 m/s
or
So, the final velocity of the electron when it reaches point B is . Hence, this is the required solution.
Answer:
The net Electric field at the mid point is 289.19 N/C
Given:
Q = + 71 nC =
Q' = + 42 nC =
Separation distance, d = 1.9 m
Solution:
To find the magnitude of electric field at the mid point,
Electric field at the mid-point due to charge Q is given by:
Now,
Electric field at the mid-point due to charge Q' is given by:
Now,
The net Electric field is given by: