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Lesechka [4]
3 years ago
13

If the torque required to loosen a nut on a wheel has a magnitude of 40.0 N·m and the force exerted by a mechanic is 133 N, how

far from the nut must the mechanic apply the force?
Question 7 options:

1.) 0.15 m
2.) 0.6 m
3.) 0.3 m
4.) 1.2 m
Physics
1 answer:
MakcuM [25]3 years ago
3 0

Answer:

3.) 0.3 m

Explanation:

Given parameters:

Torque  = 40Nm

Force = 133N

Unknown:

Distance from the nut that the mechanic must apply the force  = ?

Solution:

Torque is the force that causes an object to rotate on its axis;

  Torque  = force x distance

   Distance  = \frac{40}{133}  = 0.3m

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<span>To  neutralize the charge of 1.0g of electrons?</span>
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Andrea and the other members of the tennis team are practicing hitting tennis balls. If two people hit identical balls at the sa
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If two people hit identical tennis balls at the same time, the ball that has the most kinetic energy is the ball that moves at the fastest speed.

<u>Explanation:</u>

The energy possessed by an object by virtue of its motion is called its kinetic energy indicating that only moving objects have kinetic energy. The kinetic energy of an object depends on its speed and mass.

It is given by the expression

K=1/2 mv^2

where m denotes the mass of the object and v denotes its velocity.

since kinetic energy is directly proportional to the square of the velocity, the kinetic energy of an object increases with its velocity.

Hence an object that moves at the fastest speed will have the most kinetic energy.

8 0
3 years ago
A spring has a length of 0.200 m when a 0.300-kg mass hangs from it, and a length of 0.750 m when a 1.95-kg mass hangs from it.
Juli2301 [7.4K]

Answer:

Explanation:

The change in force = 9.81(1.95 - 0.300) = 16.2 N

The change in length is 0.750 - 0.200 = 0.550 m

K = ΔF/Δx = 16.2/0.550 = 29.4 N/m

5 0
2 years ago
Qual a massa de água a 45 °C que devemos misturar com 200 g de água a 15 °C, para que o sistema entre em equilíbrio térmico a 35
Stells [14]

Responda:

400 g

Explicação:

Dado o seguinte:

Deixe Mass (m1) = m em t1 = 45 ° C

Massa (m2) = 200g em t2 = 15 ° C

Equilíbrio térmico (T) = 35 ° C

Usando a relação:

m1 * C * ΔT = m2 * C * ΔT

Onde m1 e m2 são as massas; C = capacidade de calor específico da água e ΔT é a mudança de temperatura

m1 * ΔT = m2 * ΔT

m * (45 ° C - 35 ° C) = 200 * (35 ° C - 15 ° C)

10 * m = 200 * 20

10 * m = 4000

m = 4000/10

m = 400g

5 0
3 years ago
2. A 15.0 N force is used to hold a mass on a string at an angle of 32° from the vertical, as in the
castortr0y [4]

Answer: 2.9kg

let mass be=m ; F=15N; Sin(theta)=32°;g =9.8kgm/s^2.

represent the mass. By resolving forces, we have:

F=mgSin(theta)

15N=mgSin(32°)

m=15N/g×Sin(32°)

m=15N/9.8m/s^2÷Sin(32°)

=2.888kg2.888

≈2.9kg

5 0
3 years ago
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