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Anni [7]
3 years ago
12

You have learned of two fundamental units that are not vector quantities. Which are they?

Physics
1 answer:
Mila [183]3 years ago
4 0

Answer:

Mass and time are not vector quantities .

Explanation:

All the physical quantities can be classified into two major categories that is :

  • Scalar
  • Vector

Scalar quantities

  • They are those that describes only  the magnitude and they are regarded as incomplete quantities as they don't provide complete information.

               For example :  Speed ,Mass, Time etc

Vector quantities

  • They are complete quantities that can be described in magnitude as well as direction .

         For example : Velocity ,gravity ,Acceleration etc

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¿cual es la velocidad de un haz de electrones que marchan sin desviarse cuando pasan a traves de un campo magnetico perpendicula
Elina [12.6K]

Answer:

La velocidad del haz de electrones es 1.78x10⁵ m/s. Este valor se obtuvo asumiendo que el campo magnético dado (3500007) estaba en tesla y que la fuerza venía dada en nN.

Explanation:

Podemos encontrar la velocidad del haz de electrones usando la Ley de Lorentz:

F = |q|vBsin(\theta)     (1)

En donde:

F: es la fuerza magnética = 100 nN

q: es el módulo de la carga del electron = 1.6x10⁻¹⁹ C

v: es la velocidad del haz de electrones =?

B: es el campo magnético = 3500007 T

θ: es el ángulo entre el vector velocidad y el campo magnético = 90°

Introduciendo los valores en la ecuación (1) y resolviendo para "v" tenemos:

v = \frac{F}{qBsin(\theta)} = \frac{100 \cdot 10^{-9} N}{1.6 \cdot 10^{-19} C*3500007 T*sin(90)} = 1.78 \cdot 10^{5} m/s            

Este valor se calculó asumiendo que el campo magnético está dado en tesla (no tiene unidades en el enunciado). De igual manera se asumió que la fuerza indicada viene dada en nN.

Entonces, la velocidad del haz de electrones es 1.78x10⁵ m/s.  

Espero que te sea de utilidad!                                        

7 0
3 years ago
A wire carries 3.7 A of current. A second wire is placed parallel to the first 8.0 cm away. What is the current flowing through
IgorC [24]

Answer:

The current in second wire is 5.0 A.

(B) is correct option.

Explanation:

Given that,

Current in first wire = 3.7 A

Distance = 8.0 cm

We need to calculate the magnetic field due to the current carrying wire

Using formula of magnetic field

B=\dfrac{\mu_{0}I}{2\pi r}

Where, I = current

r = distance

Put the value into the formula

For first wire

B = \dfrac{\mu_{0}\times3.7}{2\pi \times3.4\times10^{-2}}...(I)

For second wire,

The distance is 8-3.7 =  4.3 cm

B' = \dfrac{\mu_{0}\times I'}{2\pi \times(8-3.4)\times10^{-2}}...(II)

The magnetic field in both the wires,

From equation (I) and (II)

\dfrac{\mu_{0}\times3.7}{2\pi \times3.4\times10^{-2}}= \dfrac{\mu_{0}\times I'}{2\pi \times(8-3.4)\times10^{-2}}

I'=\dfrac{3.7\times4.3\times10^{-2}}{3.4\times10^{-2}}

I'=4.68\ A\ approx = 5.0\ A

Hence, The current in second wire is 5.0 A.

8 0
4 years ago
What is the suprising thing that happens in a superconductor
ololo11 [35]
One of the most surprising things about a superconductor is that
it has NO electrical resistance. The resistance doesn't just become
very very very small.  It becomes literally completely zero. (This is
a big part of the reason why it's called a "super-conductor".)

If you start an electric current flowing in a superconductor, you can
connect the ends of it together, and the current keeps going around
and around the loop and never dies out !
5 0
3 years ago
An auto race takes place on a circular track. A car completes one lap in a time of 18.0 s, with an average tangential speed of 4
eduard

Answer:

(A) 0.3488 rad/sec

(B) 124.246 m                

Explanation:

We have given car completes one revolution in 18 sec'

So time period T= 18 sec

Tangential speed v = 43.4 m/sec

(A) Angular velocity is given by \omega =\frac{2\pi }{T}=\frac{2\times 3.14}{18}=0.3488rad/sec

(B) Tangential velocity is given v = 43.4 m /sec

We know that v=\omega r

r=\frac{v}{\omega }=\frac{43.4}{0.3488}=124.426m

4 0
3 years ago
1) What proportion of U.S. energy today comes from renewable sources? What is the most prevalent form of renewable energy used i
Rudik [331]

Answer:

Eighteen percent

Explanation:

Eighteen percent of all electricity in the US is sourced from renewable energy ,which includes solar , wind, and hydroelectric dam.

Hydroelectric power is currently the largest producer of renewable electricity in the US, generating around 6.5% of the nation's total electricity  as well as 45.71% of the total renewable electricity generation.The United States is the fourth largest producer of hydroelectricity in the world after China, Canada and Brazil.

8 0
3 years ago
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