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Anni [7]
3 years ago
12

You have learned of two fundamental units that are not vector quantities. Which are they?

Physics
1 answer:
Mila [183]3 years ago
4 0

Answer:

Mass and time are not vector quantities .

Explanation:

All the physical quantities can be classified into two major categories that is :

  • Scalar
  • Vector

Scalar quantities

  • They are those that describes only  the magnitude and they are regarded as incomplete quantities as they don't provide complete information.

               For example :  Speed ,Mass, Time etc

Vector quantities

  • They are complete quantities that can be described in magnitude as well as direction .

         For example : Velocity ,gravity ,Acceleration etc

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At the exact same instant that a
topjm [15]

Answer:

The ball being thrown straight down.

Explanation:

The downforce and  gravitational pull of the ball going down will give it

a higher velocity compared to the one trown horizontially it will take some time for it to catch downforce speed and reach the same velocity.

6 0
3 years ago
8. An ant on a picnic table travels 30 cm eastward, then 25 cm northward, and finally 15 cm westward. What is the ant's displace
wel

Answer:

The displacement of the ant, R = 29.15 cm

The angle of the resultant displacement with its original position is, θ = 30° 57'

The direction of the displacement is towards the northeast.  

Explanation:

Given data,

The displacement towards east, d₁ = 30 cm

The displacement towards north, d₂ = 25 cm

The displacement towards  west, d₃ = 15 cm

The total displacement towards east,

                                       d₄ = d₁ - d₃

                                           = 30 - 15

                                           = 15 cm

The total displacement of ant is given by the resultant displacement,

                            R = √(d₂² + d₄² + 2· d₂ d₄ CosФ)

Where Ф is the angle between the vectors, d₂ & d₄

                                                Ф = 90°

Therefore,

                               R = √(d₂² + d₄²)

Substituting in the above equation,

                               R = √(25² + 15²)

                                  = 29.15 cm

Hence, the displacement of the ant, R = 29.15 cm

The angle of the resultant displacement with its original position is,

                                θ = tan⁻¹ (d₄ / d₂)

                                   = tan⁻¹ (15 / 25)

                                   = tan⁻¹ 0.6

                                   = 30° 57'

Hence, the angle of the resultant displacement the its original position is, θ = 30° 57'

The direction of the displacement is towards the northeast.                                            

5 0
3 years ago
The movement of crustal plates is best described as a:
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5 0
3 years ago
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A helicopter carries a 1000-kg-car suspended from a rope below it. The helicopter flies horizontally at a constant speed of 25 m
kolbaska11 [484]

Answer:

(a) Tension, T = 28.653 kN

(b) Wind resistance force, 26.925\ kN

Solution:

As per the question:

Mass of the car, m = 1000 kg

Speed of the helicopter, v = 25 m/s

Angle made by the rope, theta = 20^{\circ}

Now,

(a) To calculate the tension, T in the car:

Tension along the direction of motion, T_{h} = Tcos20^{\circ}

Tension along the vertical direction, T_{v} = Tsin20^{\circ}

Now, let the force due to the wind directed in the opposite direction of the motion be F_{W} and it balances the horizontal component of the tension, T.

The vertical component is balance by the weight of the car, i.e., mg that acts vertically downwards.

Now,

T_{v} = mg

Tsin20^{\circ} = 1000\times 9.8

T = 28653 N = 28.653 kN

(b) The force of the wind resistance:

F_{W} = T_{h}

F_{W} = 2cos20^{\circ} = 26925\ N = 26.925\ kN

(c) Now,

  • If the angle made by the rope with the vertical is 0^{\circ}:

mg = Tsin(90^{\circ} - 0^{\circ})

Tsin90^{\circ} = mg = 9800\ N

The tension in the rope will be equal to the weight the car.

Wind resistance force, F_{W} = Tcos90^{\circ} = 0\ N

  • If the angle made by the rope with the vertical is 90^{\circ}:

mg = Tsin(90^{\circ} - 90^{\circ})

T = 0 N

Wind resistance force, F_{W} = Tsin0^{\circ}

Tsin0^{\circ} = mg

F_{W} = \infty

There will be no tension in the rope and wind resistance will be infinite.

3 0
3 years ago
Imagine a rock is dropped from the top of a tall building. After 2 seconds of falling, the rock’s instantaneous speed is approxi
shepuryov [24]
True
It's in free fall( 9.8 m/s), 2 seconds have passed.
3 0
3 years ago
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