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rewona [7]
3 years ago
12

Which statements describe diffraction? Check all that apply.

Physics
2 answers:
Oksi-84 [34.3K]3 years ago
8 0

Answer: Diffraction occurs when waves interact with a gap.

Diffraction occurs in any type of wave—mechanical or electromagnetic.

Explanation:

The phenomenon of light to bend around a small obstruction in its path is known as diffraction. Diffraction occurs for any type of waves- transverse or longitudinal i.e. for mechanical or electromagnetic waves.

When the medium changes- refraction occurs. Waves reflect back from a barrier. Diffraction occurs when the wavelength of the wave is comparable to the size of the gap. The wave bends around the corners of the gap.

uranmaximum [27]3 years ago
6 0
<span>-- Diffraction occurs when waves interact with a barrier.
-- Diffraction occurs when waves interact with a gap.
-- Diffraction occurs in either type of wave—mechanical or electromagnetic.</span>
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How long does it take the moon to go through an entire set of phases?.
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It take <u>approximately 29</u><u>.</u><u>5 </u><u>days</u> for moon to do its entire set of phases.

<h3>Explanation</h3>

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6 0
2 years ago
Consider a railroad bridge over a highway. A train passing over the bridge dislodges a loose bolt from the bridge, which proceed
schepotkina [342]

Answer:

12.35m

Explanation:

Hello! To solve this problem we must consider the following:

1. The car moves with constant speed, which means that the distance traveled is equal to the multiplication of time by speed.

X = VT

we solve the equation for time

T=\frac{x}{V} =\frac{27}{17} =1.588s

2. The bolt moves with constant acceleration, with acceleration of 9.81m / s ^ 2, so we could apply the following equation.

note=remember that "a uniformly accelerated motion", means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.

Y= VoT-\frac{1}{2}gt^{2}

where

Vo = Initial speed

=0

T = time

=1.588s

g =gravity=9.8m/s^2

Y =  bridge height

solving

Y= \frac{1}{2}gt^{2}\\Y=(0.5)(9.8)(1.588^2)=12.35m

4 0
3 years ago
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