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neonofarm [45]
3 years ago
6

Interference occurs with not only light waves but also all frequencies of electromagnetic waves and all other types of waves, su

ch as sound and water waves. Suppose that your physics professor sets up two sound speakers in the front of your classroom and uses an electronic oscillator to produce sound waves of a single frequency. When she turns the oscillator on (take this to be its original setting), you and many students hear a loud tone while other students hear nothing.
The professor adjusts the oscillator to produce sound waves of twice the original frequency. What happens?

a. Some of the students who originally heard a loud tone again hear a loud tone, but others in that group now hear nothing.
b. The students who originally heard a loud tone again hear a loud tone, and the students who originally heard nothing still hear nothing.
c. Among the students who originally heard nothing, some still hear nothing but others now hear a loud tone.
d. The students who originally heard a loud tone now hear nothing, and the students who originally heard nothing now hear a loud tone.

Physics
1 answer:
telo118 [61]3 years ago
4 0

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.  

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How does the temperature of water affect the speed of the sound waves?
nikitadnepr [17]

Answer:

Temperature is also a condition that affects the speed of sound. Heat, like sound, is a form of kinetic energy. Molecules at higher temperatures have more energy, thus they can vibrate faster. Since the molecules vibrate faster, sound waves can travel more quickly.

5 0
3 years ago
A mass resting on a horizontal, frictionless surface is attached to one end of a spring; the other end is fixed to a wall. It ta
Tomtit [17]

Answer:

(a) 185 N/m

(b) 3.083 kg

Explanation:

(a)

Using,

E = 1/2ke²....................... Equation 1

Where E = work done to compress the spring, k = spring constant of the spring, e = compression of the spring.

make k the subject of the equation

k = 2E/e²............... Equation 2

Given: E = 3.7 J, e = 0.20 m

Substitute into equation 2

k = 2(3.7)/0.2²

k = 185 N/m.

(b)

Using,

F = ma.............. Equation 2

Where F = force applied to the spring, m = mass attached to the spring, a = acceleration of the spring.

But from hook's law,

F = ke................. Equation 3

substitute equation 3 into equation 2

ke = ma

make m the subject of the equation

m = ke/a................ Equation 4

Given: k = 185 N/m, e = 0.2 m, a = 12 m/s²

Substitute into equation 4

m = 185(0.2)/12

m = 3.083 kg

3 0
2 years ago
Read 2 more answers
In order to move a object must have energy.<br><br> True or false and why
andriy [413]

Answer:

True

Explanation:

4 0
2 years ago
Hole filling fasteners (for example, MS20470 rivets) should not be used in composite structures primarily because of the?
DIA [1.3K]

Answer:

We can cause delamination.

Explanation:

The reason why is because the probability of causing delamination increase considerably when we use Hole-filling fasteners. If we use a typical rivet, these tends to expands in order to fill the hole.

If we analyze the force applied by the expanded rod will cause that the matrial will be deteriorated and will cause that the material to delaminate around the edges of the hole and we can cause possible control and no protection to the material.

7 0
3 years ago
You have a string with a mass of 0.0127 kg. You stretch the string with a force of 9.33 N, giving it a length of 1.93 m. Then, y
melomori [17]

Answer:

wavelength = 0.968 m

frequency = 39.02 Hz

Explanation:

given data

mass = 0.0127 kg

force = 9.33 N

length = 1.93 m

to find out

wavelength and Frequency

solution

we know here linear density that is

linear density = \frac{mass}{length}   .........1

linear density = \frac{0.0127}{1.93}

linear density = 6.5803 × 10^{-3} kg/m

so

wavelength will be here

wavelength = \frac{2L}{n}   ..............2

here n = 4 for forth harmonic

wavelength = \frac{2*1.93}{4}

wavelength = 0.968 m

and

frequency will be for 4th normal mode of vibration is

frequency = \frac{4}{2L} \sqrt{\frac{tension}{linear\ density} }    ..........3

frequency = \frac{4}{2*1.93} \sqrt{\frac{9.33}{6.5803*10^{-3}} }

frequency = 1.036269 × 37.654594

frequency = 39.02 Hz

5 0
2 years ago
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